2/3 và -6/7
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\(a,11\dfrac{3}{4}-\left(6\dfrac{5}{6}-4\dfrac{1}{2}\right)+1\dfrac{2}{3}\)
\(=\dfrac{47}{4}-\left(\dfrac{41}{6}-\dfrac{9}{2}\right)+\dfrac{5}{3}\)
\(=\dfrac{47}{4}-\left(\dfrac{41}{6}-\dfrac{27}{6}\right)+\dfrac{5}{3}\)
\(=\dfrac{47}{4}-\dfrac{14}{6}+\dfrac{5}{3}\)
\(=\dfrac{47}{4}-\dfrac{7}{3}+\dfrac{5}{3}\)
\(=\dfrac{47}{4}-\left(\dfrac{7}{3}+\dfrac{5}{3}\right)\)
\(=\dfrac{47}{4}-\dfrac{12}{3}\)
\(=\dfrac{47}{4}-4\)
\(=\dfrac{47}{4}-\dfrac{16}{4}\)
\(=\dfrac{31}{4}\)
c) Ta có: \(4\dfrac{3}{7}:\left(\dfrac{7}{5}\cdot4\dfrac{3}{7}\right)\)
\(=\dfrac{31}{7}:\left(\dfrac{7}{5}\cdot\dfrac{31}{7}\right)\)
\(=\dfrac{31}{7}:\dfrac{31}{5}\)
\(=\dfrac{5}{7}\)
a: \(=11+\dfrac{3}{13}-2-\dfrac{4}{7}-5-\dfrac{3}{13}=4-\dfrac{4}{7}=\dfrac{24}{7}\)
b: \(=\dfrac{11}{2}\cdot\dfrac{15}{4}=\dfrac{165}{8}\)
c: \(=10+\dfrac{2}{9}+2+\dfrac{3}{5}-6-\dfrac{2}{9}=6+\dfrac{3}{5}=\dfrac{33}{5}\)
d: \(=6+\dfrac{4}{9}+3+\dfrac{7}{11}-4-\dfrac{4}{9}=5+\dfrac{7}{11}=\dfrac{62}{11}\)
a, \(\Leftrightarrow2x^2=72\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow x=\pm6\)
Vậy ...
\(b,\Leftrightarrow\dfrac{3}{5}x-0,75=2\dfrac{4}{5}.\dfrac{3}{7}=\dfrac{6}{5}\)
\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{6}{5}+0,75=\dfrac{39}{20}\)
\(\Leftrightarrow x=\dfrac{39}{20}:\dfrac{3}{5}=\dfrac{13}{4}\)
Vậy ...
\(c,\Leftrightarrow2x=1\dfrac{5}{6}.\dfrac{6}{11}-\dfrac{3}{10}=\dfrac{7}{10}\)
\(\Leftrightarrow x=\dfrac{7}{10}:2=\dfrac{7}{20}\)
Vậy ...
\(d,\Leftrightarrow\dfrac{1}{x-7\dfrac{1}{3}}=1.5:2\dfrac{1}{4}=\dfrac{2}{3}\)
\(\Leftrightarrow x-7\dfrac{1}{3}=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{3}{2}+7\dfrac{1}{3}=\dfrac{53}{6}\)
Vậy ...
a) 2x2 - 72 = 0
\(\Rightarrow\) 2x2 = 72
\(\Rightarrow\) x2 = 36 = 62 = (- 6)2
\(\Rightarrow\) x = 6 hoặc x = - 6
Vậy x = 6 hoặc x = - 6
b) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(2\dfrac{4}{5}\)
\(\Rightarrow\) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(\dfrac{14}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x - \(\dfrac{3}{4}\) = \(\dfrac{6}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x = \(\dfrac{39}{20}\)
\(\Rightarrow\) x = \(\dfrac{13}{4}\)
Vậy x = \(\dfrac{13}{4}\)
1)2/6=14/42 2)5/9=25/45
4/7=24/42 6/5=54/45
3)7/2=28/8 4)4/9=28/63
5/8 =5/8 8/7=72/63
CÁC Ý CÒN LẠI BẠN LÀM NỐT NHÉ
2/6 và 4/7
Mẫu số chung:42
\(\frac{2}{6}=\frac{2\times7}{6\times7}=\frac{14}{42}\);\(\frac{4}{7}=\frac{4\times6}{7\times6}=\frac{24}{42}\)
5/9 và 6/5
Mẫu số chung: 45
\(\frac{5}{9}=\frac{5\times5}{9\times5}=\frac{25}{45}\); \(\frac{6}{5}=\frac{6\times9}{5\times9}=\frac{54}{45}\)
7/2 và 5/8
Mẫu số chung:8
\(\frac{7}{2}=\frac{7\times4}{2\times4}=\frac{28}{8}\);\(\frac{5}{8}\)
4/9 và 8/7
Mẫu số chung: 63
\(\frac{4}{9}=\frac{4\times7}{9\times7}=\frac{28}{63};\frac{8}{7}=\frac{8\times9}{7\times9}=\frac{72}{63}\)
9/4 và 2/6
Mẫu số chung:12
\(\frac{9}{4}=\frac{9\times3}{4\times4}=\frac{27}{12};\frac{2}{6}=\frac{2\times2}{6\times2}=\frac{4}{12}\)
4/3 và 9/4
Mẫu số chung:12
\(\frac{4}{3}=\frac{4\times4}{3\times4}=\frac{16}{12}\);\(\frac{9}{4}=\frac{9\times3}{4\times3}=\frac{27}{12}\)
\(3\dfrac{7}{4}-7\dfrac{2}{3}+4\dfrac{1}{6}+\dfrac{1}{2}\)
\(=\dfrac{19}{4}-\dfrac{23}{3}+\dfrac{25}{6}+\dfrac{1}{2}\)
\(=\dfrac{57}{12}-\dfrac{92}{12}+\dfrac{50}{12}+\dfrac{6}{12}\)
\(=\dfrac{21}{12}\)
\(=\dfrac{7}{4}\)
#\(Toru\)