giúp mình với, mình đang cần gấp ạ: (-x- 5)- (10- 2x)= -5
-3(x+ 3)+ 5(x-1)= -10
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\(a,\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x^3=-8\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\\ b,\Leftrightarrow4x-3-x-5=30-3x\\ \Leftrightarrow4x-x+3x=30+5+3\\ \Leftrightarrow6x=38\\ \Leftrightarrow x=\dfrac{19}{3}\)
\(\left(6:3,5-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\\ =\left(\dfrac{12}{7}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\\ =\left(\dfrac{17}{7}-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)\\ =\dfrac{10}{7}:9\\ =\dfrac{10}{63}\)
\(\left(6:\dfrac{3}{5}-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\)
\(=\left(6\times\dfrac{5}{3}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\)
\(=\left(10-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)=9:9=1\)
a)
\(\frac{x-3}{10}=\frac{4}{x-3}\)
=> ( x - 3 )2 = 4 . 10.
( x - 3 )2 = 40
Mà x - 3 thuộc Z ( vì x thuộc Z ) nên ( x - 3 )2 là số chính phương.
Do 40 không là số chính phương.
=> Ko tìm được x thuộc Z thỏa mãn đề bài.
b)
\(\frac{x+5}{9}=\frac{4}{x+5}\)
=> ( x + 5 )2 = 4 . 9
( x + 5 )2 = 36
=> x + 5 = 6 hoặc x + 5 = -6.
+) x + 5 = 6
x = 1.
+) x + 5 = -6
x = -11.
Vậy x = 1; x = -11.
a) x. -5/3 = 1
=> x = 1 : -5/3
=> x = -3/5
b) x : 17/8 = (-2). -9/17
=> x : 17/8 = 18/17
=> x = 18/17 . 17/8
=> x = 9/4
c) x . 1/5 . 7/10 = 1
=> x . 7/50 = 1
=> x = 1 : 7/50
=> x = 50/7
Chúc bạn học tốt
a) \(x=1:\frac{-5}{3}=\frac{1.-3}{5}=\frac{-3}{5}\)
b) \(x:\frac{17}{8}=-2.\frac{-9}{17}=\frac{18}{17}\)
\(x=\frac{18}{17}.\frac{17}{8}=\frac{18}{8}=\frac{9}{4}\)
c) \(x=1:\frac{7}{10}:\frac{1}{5}=1.\frac{10}{7}.5=5.\frac{10}{7}=\frac{50}{7}\)
Chúc bạn học tốt!!!
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
Bài 2:
a) Ta có: \(\left|2x-5\right|\ge0\forall x\)
\(\Leftrightarrow-\left|2x-5\right|\le0\forall x\)
\(\Leftrightarrow-\left|2x-5\right|+3\le3\forall x\)
Dấu '=' xảy ra khi \(x=\dfrac{5}{2}\)
Ta có : |2x - 5| + |4 + x| = 0
Mà : |2x - 5| \(\ge0\forall x\)
|4 + x| \(\ge0\forall x\)
Nên \(\orbr{\begin{cases}\left|2x-5\right|=0\\\left|4+x\right|=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-5=0\\4+x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=5\\x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{2}\\x=-4\end{cases}}\)
-3x+(-9)+5x-5=-10
(-3x+5x)+(-9-5)=-10
-2x+(-14)=-10
-2x=-10-(-14)
-2x=24
x=24:(-2)
x=-12. chúc bạn học tối nha