125 : x - 80 : x = 9
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\(\dfrac{31}{48}\times\dfrac{32}{93}\)
\(=\dfrac{31\times32}{48\times93}\)
\(=\dfrac{1\times2}{3\times3}\)
\(=\dfrac{2}{9}\)
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\(\dfrac{77}{80}\times\dfrac{48}{49}\)
\(=\dfrac{77\times48}{80\times49}\)
\(=\dfrac{11\times3}{5\times7}\)
\(=\dfrac{33}{35}\)
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\(\dfrac{154}{125}\times\dfrac{25}{44}\)
\(=\dfrac{154}{125}\times\dfrac{25}{44}\)
\(=\dfrac{7\times1}{5\times2}\)
\(=\dfrac{7}{10}\)
( y - 1 ) : 105 = 125 x 80
( y - 1 ) : 105 = 10000
y - 1 = 10000 x 105
y - 1 = 1050000
y = 1050000 + 1
y = 1050001
2)a)
(-125)+100-80+125-20
=(-125+125)+(-80+-20)+100
=0+-100+100=0
b)
-30-(95+(-40)+5+(-30)
=-30-((95+5)+(-40+-30)
=-30-(100+(-70))
=-30-30=-60
`5 xx 74 xx 2 = 5xx 2 xx 74 = 10xx74 = 740`
`4xx196xx5 = 4xx5xx196 = 20xx196 = 3920`
`(50 + 25)xx4 = 50xx4 + 25xx4 = 200 + 100 = 300`
`125xx(80+8) = 125xx80 + 125xx8 = 10000 + 1000 = 11000`
\(\left\{240-\left[76-\left(9-3\right)^2\right]\right\}\div50=\left\{240-\left[76-6^2\right]\right\}\div50=\left\{240-\left[76-36\right]\right\}\div50\)
\(=\left\{240-40\right\}\div50=200\div50=4\)
Tìm x :
\(\left(2+x\right)\div5=6\)
\(2+x=6.5\)
\(2+x=30\)
\(x=30-2\)
\(x=28\)
\(2+x\div5=6\)
\(x\div5=6-2\)
\(x\div5=4\)
\(x=4.5\)
\(x=20\)
So sánh :
a) Ta có : \(125^{80}=\left(5^3\right)^{80}=5^{240}\)
\(25^{118}=\left(5^2\right)^{118}=5^{236}\)
mà \(240>236\)
\(\Rightarrow5^{240}>5^{236}\)
\(\Rightarrow125^{80}>25^{118}\)
b) Ta có : \(2^{161}>2^{160}=\left(2^4\right)^{40}=16^{40}>13^{40}\)
\(\Rightarrow2^{161}>13^{40}\)
125:x-80:x=9
(125-80):x=9
45:x=9
x=45:9
x=5