327 : x – 112 : x = 5
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326 x 78 + 327 x 22
= 326 x 78 + (326 + 1) x 22
= 326 x 78 + 326 x 22 + 1 x 22
= 326 x (78 + 22) + 22
= 326 x 100 + 22
= 32600 + 22
= 32622
Vậy giá trị cầ tìm là: 32622
4 x 113 x 25 - 5 x 112 x 20
= 4 x 25 x 113 - 5 x 20 x 112
= 100 x 113 - 100 x 112
= 100 x (113 - 112)
= 100 x 1
= 100
Vậy giá trị cần tìmlaf 100
hok tốt
Sửa đề: Tìm x \(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)
Bài giải
\(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)
\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329+20}{5}=0\)
\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329}{5}+\dfrac{20}{5}=0\)
\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329}{5}+4=0\)
\(\Leftrightarrow\dfrac{x+2}{327}+1+\dfrac{x+3}{326}+1+\dfrac{x+4}{325}+1+\dfrac{x+5}{324}+1+\dfrac{x+329}{5}=0\)
\(\Leftrightarrow\dfrac{x+329}{327}+\dfrac{x+329}{326}+\dfrac{x+329}{325}+\dfrac{x+329}{324}+\dfrac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\left(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+\dfrac{1}{324}+\dfrac{1}{5}\right)=0\)
\(\Rightarrow x+329=0\). Do \(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+\dfrac{1}{324}+\dfrac{1}{5}\ne0\)
\(\Rightarrow x=-329\)
a, 315-x=327-264
<=> 315-x=63
<=> x=315-63
<=>x=252
b, 147-x=10 x 5
<=> 147-x=50
<=> x= 147-50
<=> x=97
\(\left(315-x\right)+264=327\)
\(\left(315-x\right)=63\)
\(x=315-63\)
\(x=252\)
\(\left(147-x\right):5=10\)
\(\left(147-x\right)=50\)
\(x=147-50\)
\(x=97\)
327 : x - 112 : x = 5
=(327-112) : x = 5
=215 : x = 5
=215 x 5
=1075