Tính nhanh : (45-712)-(888-55)
Giúp mik vs
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, = (-8014) -273 +8104
= (-8014) +8104 -273
=-273
b, =45-712 -888+55
=45+55 -712-888
=100-1600
= -1500
Chúc bạn thi tốt nha!
<=>x-45/55 -1 + x-47/53 -1=x-55/45 -1 + x-53/47-1
<=>x-100/55 + x-100/53 = x-100/45 + x-100/47
<=>(x-100)(1/55 + 1/53 - 1/45 - 1/47 )=0
vi (1/55 + 1/53 - 1/45 - 1/47 ) luon khac 0 nen x-100=0 <=>x=100
a, 399.45 + 55.399
= 399 ( 45 + 55 )
= 399. 100
= 39900
b, 1995.1996 - 1991.1995
= 1995 ( 1996 - 1991 )
= 1995 . 5
= 9975
A)399x45+55x399
=399x(45+55)
=399x100
=3990
b)1995.1996-1991.1995
=1995.(1996-1991)
=1995.5
=9975
`@` `\text {Ans}`
`\downarrow`
`a)`
`-(-18 + 45) - (18 + 55)`
`= 18 - 45 - 18 - 55`
`= (18 - 18) - (45 + 55)`
`= -100`
`b)`
`24. (5 - 178) + 178 . (10 + 24)`
`= 24.5 - 24.178 + 178. 10 + 178. 24`
`= 24.5 + 178.(-24 + 10 + 24)`
`= 24.5 + 178.10`
`=120 + 1780`
`=``1900`
`c)`
`29.(-101)`
`= -2929`
`d)`
\((- 56 + 130) – (43 – 56) – (- 20 – 43)\)
`= -56 + 130 - 43 + 56 + 20 + 43`
`= (56 - 56) + (130 + 20) + (-43+43)`
`= 150`
Ta có: \(M=\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}\)
\(\Leftrightarrow\frac{1}{2}M=\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}\)
\(\Leftrightarrow\frac{1}{2}M=\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}\)
\(\Leftrightarrow\frac{1}{2}M=\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{10}-\frac{1}{11}=\frac{1}{6}-\frac{1}{11}=\frac{5}{66}\)
\(\Rightarrow M=\frac{5}{66}:\frac{1}{2}=\frac{5}{33}.\)
\(M=\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}\)
\(M=\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+\frac{2}{90}+\frac{2}{110}\)
\(M=\frac{2}{6\cdot7}+\frac{2}{7\cdot8}+\frac{2}{8\cdot9}+\frac{2}{9\cdot10}+\frac{2}{10\cdot11}\)
\(M=2\left(\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}+\frac{1}{10\cdot11}\right)\)
\(M=2\left(\frac{1}{6}-\frac{1}{11}\right)\)
\(M=2\cdot\frac{5}{66}\)
\(M=\frac{5}{33}\)
a, 1 + 2 + 3 + ... + 87
= (1 + 87).87 : 2
= 87.88 : 2
= 87.44
= 3828
b, 2 + 4 + 6 + ... + 54
= (2 + 54).27 : 2
= 27.56 : 2
= 27.28
= 756
c, 3 + 6 + 9 + ... + 99
= (99 + 3).49 : 2
= 49.102 : 2
= 49.51
= 2499
d, 45.25 + 45.75 + 55.25.25 + 55.75
= 45. (25 + 75) + 55(25.25 + 75)
= 45.100 + 55.700
= 4500 + 38500
= 43000
\(d,45x25+45x75+55x25+55x75\)
\(=45x\left(25+75\right)+55x\left(25+75\right)\)
\(=45x100+55x100\)
\(=100x\left(45+55\right)\)
\(=100x100\)
\(=10000\)
a) \(\frac{x-45}{55}+\frac{x-47}{53}=\frac{x-55}{45}+\frac{x-53}{47}\)
\(\Leftrightarrow\left(\frac{x-45}{55}-1\right)+\left(\frac{x-47}{53}-1\right)=\left(\frac{x-55}{45}-1\right)+\left(\frac{x-53}{47}-1\right)\)
\(\Leftrightarrow\frac{x-100}{55}+\frac{x-100}{53}=\frac{x-100}{45}+\frac{x-100}{47}\)
\(\Leftrightarrow\frac{x-100}{55}+\frac{x-100}{53}-\frac{x-100}{45}-\frac{x-100}{47}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{55}+\frac{1}{53}-\frac{1}{45}-\frac{1}{47}\right)=0\)
Vì \(\hept{\begin{cases}\frac{1}{55}< \frac{1}{45}\\\frac{1}{53}< \frac{1}{47}\end{cases}}\Rightarrow\frac{1}{55}+\frac{1}{53}-\frac{1}{45}-\frac{1}{47}< 0\)
\(\Rightarrow x-100=0\Rightarrow x=100\)
Vậy x = 100
(45-712)-(888-55)
= 45-712-888+55
=(45+55)+[(-712)+(-888)]
= 100+(-1600)
= -1500
HT và $$$