64+ 24=?
giúp e nhé
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mấy cái câu đầu thì tớ ko hiểu !(thông cảm)
17/60-5/18-64/90= -127/180
ko chắc là đúng^
a)\(x^4+64=x^4+16x^2+64-16x^2\)
\(=\left(x^2\right)^2+2.x^2.8+8^2-\left(4x\right)^2\)
\(=\left(x^2+8\right)^2-\left(4x\right)^2\)
\(=\left(x^2+8-4x\right)\left(x^2+8+4x\right)\)
b)\(4x^4+81=4x^4+36x^2+81-36x^2\)
\(=\left(2x^2\right)^2+2.2x^2.9+9^2-\left(6x\right)^2\)
\(=\left(2x^2+9\right)^2-\left(6x\right)^2\)
\(=\left(2x^2+9-6x\right)\left(2x^2+9+6x\right)\)
c)\(x^4y^4+64=x^4y^4+16\left(xy\right)^2+64-16\left(xy\right)^2\)
\(=\left[\left(xy\right)^2\right]^2+2.\left(xy\right)^2.8+8^2-\left(8xy\right)^2\)
\(=\left[\left(xy\right)^2+8\right]^2-\left(8xy\right)^2\)
\(=\left[\left(xy\right)^2+8-8xy\right]\left[\left(xy\right)^2+8+8xy\right]\)
a,
\(\left(325-47\right)+\left(175-53\right)\\ =325-47+175-53\\ =325+175-47-53\\ =\left(325+175\right)-\left(47+53\right)\\ =500-100\\ =400\)
b,
\(\left(756-217\right)-\left(183-53\right)\\ =756-217-183+53\\ =756+53-217-183\\ =\left(756+53\right)-\left(217+183\right)\\ =809-400\\ =409\)
c,
\(\left(-5\right)\cdot6\cdot\left(-2\right)\cdot7\\ =\left[\left(-5\right)\cdot\left(-2\right)\right]\cdot\left(6\cdot7\right)\\ =10\cdot42\\ =420\)
d,
\(24\cdot36-\left(-24\right)\cdot64\\ =24\cdot36+24\cdot64\\ =24\cdot\left(36+64\right)\\ =24\cdot100\\ =2400\)
e,
\(24\cdot36-\left(-24\right)\cdot64\\ =24\cdot36+24\cdot64\\ =24\cdot\left(36+64\right)\\ =24\cdot100\\ =2400\)
Bài 1: Tính:
a) (325+175) - (47+53)
= 500-100=400.
b) (756-217) - (183-53)
= 539-150= 389.
c) (-5).(-2).6.7
= 10.42=420
d) 24.36- (-24).64
= 864- (-1536)
= 2400.
Tick mk nha bn!!!!!
(Vẫn rút gọn hở ?)
4. \(\frac{64^3.36^2}{16^4.18^5}=\frac{\left(2^6\right)^3.\left(2^2.3^2\right)^2}{\left(2^4\right)^4.\left(2.3^2\right)^5}=\frac{2^{18}.\left(2^2\right)^2.\left(3^2\right)^2}{2^{16}.2^5.\left(3^2\right)^5}\)
\(=\frac{2^{18}.2^4.3^4}{2^{16}.2^5.3^{10}}=\frac{2^{22}.3^4}{2^{21}.3^{10}}=\frac{2}{3^6}\)
5. \(\frac{34^{18}.68^{24}}{17^{30}.2^{16}}=\frac{\left(2.17\right)^{18}.\left(2^2.17\right)^{24}}{17^{30}.2^{16}}=\frac{2^{18}.17^{18}.\left(2^2\right)^{24}.17^{24}}{17^{30}.2^{16}}\)
\(=\frac{2^{18}.17^{18}.2^{48}.17^{24}}{17^{30}.2^{16}}=\) \(\frac{2^{66}.17^{42}}{17^{30}.2^{16}}=2^{50}.17^{12}\)
64+ 24=?
TL :
64+ 24=88
HT