Tìm y, biết (56+y) - (67-71) = 25
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15/5x38/5=22.8
67/15+56/15=8.2
Nếu X là: số tự nhiên thì X=9;10;11;12;13;14;15;16;17;18;19;20;21;22
Còn nếu khác thì bạn dựa vào kết quả mình đã ra để tìm số
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x + 34 = 56 - 6
x + 34 = 50
x = 50 - 34
x = 16
y + 56 = 78 + 4
y + 56 = 82
y = 82 - 56
y = 26
x + 32 = 345
x = 345 - 32
x = 313
y + 67 - 6 = 89 - 0
y + 67 - 6 = 89
y + 67 = 89 + 6
y + 67 = 95
y = 95 - 67
y = 28
x + 34 = 56 - 6
x + 34 = 50
x = 50 - 34
x = 16
y + 56 = 78 + 4
y + 56 = 82
y = 82 - 56
y = 26
x + 32 = 345
x = 345 - 32
x = 313
y + 67 - 6 = 89 - 0
y + 67 - 6 = 89
y + 67 = 89 + 6
y + 67 = 95
y = 95 - 67
y = 28
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12160−y=5×67×20
12160−y=67×(5×20)
12160−y=67×100
12160−y=6700
y=12160−6700
y=5460
Đáp án A
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1)
3,54 . 73 + 0,23 . 25 + 3,54 . 27 + 0,17 . 25
=3,54 . (73 + 27) + 25 . (0,23 + 0,17)
=3,54 . 100 + 25 . 0,4
=354 + 10
=364
2)
15/19 . 38/5 < x < 67/15 + 56/15
=> 15.38/19.5 < x < 67+56/15
-> 6 < x < 8,2
Vậy x là 7, 8
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Ta có: \(71+\left(65\times4\right)=\frac{y+140}{y+260}\)
\(\Leftrightarrow331=\frac{y+140}{y+260}\)
\(\Leftrightarrow331\left(y+260\right)=y+140\)
\(\Leftrightarrow331y+86060=y+140\)
\(\Leftrightarrow331y-y=140-86060\)
\(\Leftrightarrow330y=-85920\)
\(\Leftrightarrow y=\frac{-85920}{330}=\frac{-2864}{11}\)
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Ta có:
15/19 × 38/5 = 6
67/15 + 56/15 = 123/15 = 8,2
Mà 6 < X < 8,2
Vậy X = 6 hoặc X = 7
(56+y) - (-4) =25
(56+y) =25 + (-4)
56+y =21
y = 21-56
y = -35
HT