263 : 32 = ?
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a) 4838
b) -133
c) 123.5356415
BẠN LÀM TỐT NHÉ ):
KẾT BẠN VỚI TỚ NHÉ
a) 34.(-84) + 17.(-32)
= 17.2.(-84) + 17 .(-32)
= 17. (-168) + 17.(-32)
= 17.(-168 - 32)
= 17. (-200)
= -3400
b) 4524 + (-864) + 9999 + (-36) + ( -8999)
= 4524 - 864 + 9999 - 36 - 8999
= 3660 + (9999 - 8999) - 36
= 3660 + 1000 - 36
= 4624
c) 1000 + (-137) + 263 + (-572) + (-291)
= 1000 - 137 + 263 - 572 - 291
= 263
d) (-329) + 15 + (-101) + 440 + (-25)
= 15 - 329 - 101 + 440 - 25
= 0
\(a.\)
\(34.\left(-84\right)+17.\left(-32\right)\)
\(=17.\left(-168\right)+17.\left(-32\right)\)
\(=17.\left(-168+-32\right)\)
\(=17.\left(-200\right)\)
\(=-3400\)
\(b.\)
\(4524+\left(-864\right)+9999+\left(-36\right)+\left(-8999\right)\)
\(=\left[4524+\left(-864\right)\right]+\left[9999+\left(-8999\right)\right]+\left(-36\right)\)
\(=3660+1000+\left(-36\right)\)
\(=4624\)
\(c.\)
\(1000+\left(-137\right)+263+\left(-572\right)+\left(-291\right)\)
\(=\left[263+\left(-572\right)+\left(-291\right)\right]+1000+\left(-137\right)\)
\(=\left(-600\right)+1000+\left(-137\right)\)
\(=400+\left(-137\right)\)
\(=263\)
\(d.\)
\(\left(-329\right)+15+\left(-101\right)+440+\left(-25\right)\)
\(=\left[15+\left(-25\right)\right]+\left[440+\left(-101\right)+\left(-329\right)\right]\)
\(=\left(-10\right)+10\)
\(=0\)
a) -23.63 + 23.21-58.23
=-1449+483-1334
=-966-1334
=-2300
b) (-67).75 + 75.(-33)
=75.[-67+(-33)]
=75.(-100)
=-7500
c)(-5).8.(-2).3
=-40.(-6)
=240
d) (-163)+177+263-377
=[(-163) + 263] + (377-177)
=100+200
=300
e) (-2)^4.17+(-7).16
=-16.17+(-112)
=-272+(-112)
=-384
f) 125-(-75) + 32-(48+32)
=87 + 32-80
=87-80+32
=7+32
=39
Bài 1:
a) \(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
b) \(100^2+103^2+105^2+94^2=101^2+98^2+96^2+107^2\)
\(\Leftrightarrow100^2+103^2+105^2+94^2-101^2-98^2-96^2-107^2=0\)
\(\Leftrightarrow\left(100^2-98^2\right)+\left(103^2-101^2\right)-\left(107^2-105^2\right)-\left(96^2-94^2\right)=0\)
\(\Leftrightarrow2.198+2.204-2.212-2.190=0\)
\(\Leftrightarrow2\left(198+204-212-190\right)=0\)
\(\Leftrightarrow2.0=0\) (đúng)
Bài 2:
a) \(263^2+74.263+37^2\)
\(=263^2+2.37.263+37^2\)
\(=\left(263+37\right)^2\)
b) \(\left(50^2+48^2+46^2+...+2^2\right)-\left(49^2+47^2+45^2+...+1^2\right)\)
\(=50^2+48^2+46^2+...+2^2-49^2-47^2-45^2-...-1^2\)
\(=\left(50^2-49^2\right)+\left(48^2-47^2\right)+\left(46^2-45^2\right)+...+\left(2^2-1^2\right)\)
\(=\left(50+49\right)+\left(48+47\right)+\left(46+45\right)+...+\left(2+1\right)\)
\(=50+49+48+47+46+45+...+2+1\)
\(=\dfrac{\left(50+1\right).\left(50-1+1\right)}{2}=1275\)
Kết luận ...
\(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
\(263^2+74\cdot263+37^2\)
\(=263^2+2\cdot37\cdot263+37^2\)
\(=\left(363+37\right)^2\)
\(=400^2\)
- 263 + 177 + 263 - 77
= ( -263 + 263 ) + ( 177 -77 )
= 0 + 100
= 100
của bạn đây
- 263 + 177 + 263 -77
= [ ( - 268) + 263 ] + [ 177 + ( -77) ]
= 0 + 100
= 100
Tick cho tớ nh, chúc bn học tốt
\(B=263^2+74.263+37^2\)
\(=\left(263+37\right)^2\)
\(=300^2\)
\(=90000\)
\(B=263^2+74\cdot263+37^2\)
\(=263^2+2\cdot263\cdot37+37^2\)
\(=\left(263+37\right)^2\)
\(=300^2\)
\(=90000\)
263 : 32 = 8,21875
263 : 32 = 8,21875