Tim x:
x + 15 = 45 - 25
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x:x*15-3,7=2,3
x:2*15-3,7=2,3
x:2*15=2,3+3,7
x:2*15=6
x:2=6:15
x*2=0,4
x=0,4:2
x=0,2
\(x^5+x^4+x+1=0\)
\(\Leftrightarrow x+1=0\)
hay x=-1
\(x^3-5x^2-9x+45=0\)
=>\(x^2\left(x-5\right)-9\left(x-5\right)=0\)
=>\(\left(x-5\right)\left(x^2-9\right)=0\)
=>\(\left(x-5\right)\left(x-3\right)\left(x+3\right)=0\)
=>\(\left[{}\begin{matrix}x-5=0\\x-3=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=3\\x=-3\end{matrix}\right.\)
`x^3 -5x^2 -9x+45=0`
`<=> (x^3 -5x^2 )-(9x-45)=0`
`<=> x^2 (x-5)- 9(x-5)=0`
`<=>(x-5)(x^2 -9)=0`
`<=>(x-5)(x-3)(x+3)=0`
\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\\x-3=0\\x+3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=3\\x=-3\end{matrix}\right.\)
a )
\(x+\frac{12}{15}=\frac{7}{5}\)
\(\Rightarrow x=\frac{7}{5}-\frac{12}{15}\)
\(\Rightarrow x=\frac{7}{5}-\frac{4}{5}\)
\(\Rightarrow x=\frac{3}{5}\)
Vậy \(x=\frac{3}{5}\)
b )
\(x-\frac{6}{8}=\frac{3}{15}\)
\(\Rightarrow x-\frac{3}{4}=\frac{1}{5}\)
\(\Rightarrow x=\frac{1}{5}+\frac{3}{4}\)
\(\Rightarrow x=\frac{4}{20}+\frac{15}{20}\)
\(\Rightarrow x=\frac{19}{20}\)
Vậy \(x=\frac{19}{20}\)
~ Ủng hộ nhé
\(x+\frac{12}{15}=\frac{7}{5}\)
\(\Rightarrow x=\frac{7}{5}-\frac{12}{15}\)
\(\Rightarrow x=\frac{7}{5}-\frac{4}{5}\)
\(\Rightarrow x=\frac{3}{5}\)
\(x^{15}=x\)
\(\Rightarrow x^{15}-x=0\)
\(\Rightarrow x.\left(x^{14}-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^{14}=0+1=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
25 + 25 + 25 + 25 + 25 + 25 +25 + 25=25x8=200
45 + 45 + 45 + 45 + 15 + 15 + 15 + 15=(45x4)+(15x4)=180+60=240
x + 15 = 45 - 25
x +15 = 20
x = 20 - 15 (TSH)
x = 5
x+15=45-25=20
x=20-15
x=5
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