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|x+1|-x+2=3-x
|x+1| = 3 - x - 2 + x
|x+1| = 1
\(\Rightarrow\orbr{\begin{cases}x+1=1\\x+1=-1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)
Vậy x \(\in\left\{0;-2\right\}\)
Hok tốt !
\(|x+1|-x+2=3-x\)
\(\Leftrightarrow|x+1|-x+2-3+x=0\)
\(\Leftrightarrow|x+1|-1=0\)
\(\Leftrightarrow|x+1|=1\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=1\\x+1=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}}\)
A\(\frac{7}{15}+\frac{4}{5}=\frac{7}{15}+\frac{12}{15}=\frac{19}{15}\)
B\(\frac{2}{3}-\frac{3}{8}=\frac{16}{24}-\frac{9}{24}=\frac{7}{24}\)
C\(\frac{4}{5}\times\frac{5}{8}=\frac{20}{40}=\frac{1}{2}\)
D\(4:\frac{3}{2}=\frac{4}{1}\times\frac{2}{3}=\frac{8}{3}\)
Bài 1
1 has been examining
3 has just finished
3 has taught
4 has been crying
5 has been cleaning
7 has done
8 has just broken
Bài 2
2 was making
3 was looking
4 was reading
5 were studying
a: Xét ΔABC có BM/BC=BD/BA
nên MD//AC
=>MM' vuông góc AB
=>M đối xứngM' qua AB
b: Xét tứ giác AMBM' có
D là trung điểm chung của AB và MM'
MA=MB
Do đó: AMBM' là hình thoi
Bài 3
2 was
3 loved
4 cared
5 died
B
1 decided
2 got
3 was flying - were playing
5 asked
6 was enjoying
7 covered
Bài 4
1 used to
2 used to
4 didn't use to
5 didn't use to
Bài 5
2 live
3 watch
4 going
5 ride
6 washing
khó nhìn z :)))
ko thấy bạn ơi