rút gọn A=4^10.9^6+9612+8^5/6^13.4-2^16.312
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11 tháng 11 2021
\(=\dfrac{2^{20}\cdot3^{12}+3^{12}\cdot2^{15}}{2^{15}\cdot3^{13}-2^{16}\cdot3^{12}}\)
\(=\dfrac{2^{15}\cdot3^{12}\left(2^5+1\right)}{2^{15}\cdot3^{12}\left(3-2\right)}\)
=33
HT
0
DD
1
YN
15 tháng 2 2023
a) \(\dfrac{5}{6}-\dfrac{2}{14}\)
\(=\dfrac{5}{6}-\dfrac{1}{7}\)
\(=\dfrac{35}{42}-\dfrac{6}{42}\)
\(=\dfrac{29}{42}\)
b) \(\dfrac{5}{20}-\dfrac{1}{6}\)
\(=\dfrac{1}{4}-\dfrac{1}{6}\)
\(=\dfrac{3}{12}-\dfrac{2}{12}\)
\(=\dfrac{1}{12}\)
c) \(\dfrac{5}{9}-\dfrac{3}{12}\)
\(=\dfrac{5}{9}-\dfrac{1}{4}\)
\(=\dfrac{20}{36}-\dfrac{9}{36}\)
\(=\dfrac{11}{36}\)
d) \(8-\dfrac{4}{6}\)
\(=\dfrac{48}{6}-\dfrac{4}{6}\)
\(=\dfrac{44}{6}=\dfrac{22}{3}\).
28 tháng 10 2023
a: \(\dfrac{1}{8}+\dfrac{5}{8}=\dfrac{1+5}{8}=\dfrac{6}{8}=\dfrac{3}{4}\)
b: \(\dfrac{1}{15}+\dfrac{4}{15}=\dfrac{1+4}{15}=\dfrac{5}{15}=\dfrac{1}{3}\)
c: \(\dfrac{5}{9}+\dfrac{7}{9}=\dfrac{5+7}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)
d: \(\dfrac{23}{100}+\dfrac{27}{100}=\dfrac{23+27}{100}=\dfrac{50}{100}=\dfrac{1}{2}\)
S
16 tháng 3 2017
a) \(3-\frac{6}{8}-\frac{2}{4}\)
\(=\frac{18}{8}-\frac{6}{8}-\frac{4}{8}\)
\(=\frac{18-6-4}{8}\)
\(=\frac{8}{8}=1\)
b) \(\frac{5}{6}-\frac{1}{2}+2\)
\(=\frac{5}{6}-\frac{3}{6}+\frac{12}{6}\)
\(=\frac{5-3+12}{6}\)
\(=\frac{14}{6}=\frac{7}{3}\)
SY
16 tháng 3 2017
\(a.3+\frac{6}{8}-\frac{2}{4}\\ =\frac{3}{1}+\frac{6}{8}-\frac{2}{4}\\ =\frac{24}{8}+\frac{6}{8}-\frac{4}{8}\\ =\frac{24+6-4}{8}\\ =\frac{26}{8}\\ =\frac{13}{4}\)
\(b.\frac{5}{6}-\frac{1}{2}+2\\ =\frac{5}{6}-\frac{1}{2}+\frac{2}{1}\\ =\frac{5}{6}-\frac{3}{6}+\frac{12}{6}\\ =\frac{5-3+12}{6}\\ =\frac{14}{6}\\ =\frac{7}{3}\)
VD
4
S
1 tháng 7 2018
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-2}{6}=-\frac{1}{3}\)
1 tháng 7 2018
Ta có:\
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
\(A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(A=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(A=-\frac{2}{6}=-\frac{1}{3}\)
L
4
S
5 tháng 1 2023
\(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3-1\right)}\)
\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^{12}.3^{10}.6}{2^{11}.3^{11}.5}=\dfrac{2.6}{3.5}=\dfrac{4}{5}\)
