484848/323232=6*.../72
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\(\frac{484848}{323232}=\frac{48x10101}{32x10101}=\frac{48}{32}=\frac{6}{4}=\frac{6x18}{4x18}=\frac{6x18}{72}\)
\(\frac{222222}{323232}=\frac{222222:20202}{323232:20202}=\frac{11}{16}\)
\(\frac{121212}{484848}=\frac{121212:121212}{484848:121212}=\frac{1}{4}\)
\(\frac{5555}{7575}=\frac{5555:505}{7575:505}=\frac{11}{15}\)
\(\frac{1111}{5656}=\frac{1111:101}{5656:101}=\frac{11}{56}\)
\(\frac{1919}{4141}=\frac{1919:101}{4141:101}=\frac{19}{41}\)
\(\frac{1515}{4545}=\frac{1515:1515}{4545:1515}=\frac{1}{3}\)
\(\frac{1515}{3636}=\frac{1515:303}{3636:303}=\frac{5}{12}\)
\(\frac{121212}{161616}-\left(\frac{151515}{323232}-x\right)=2\)
=> \(\frac{3}{4}-\left(\frac{15}{32}-x\right)=2\)
=> \(\frac{15}{32}-x=\frac{3}{4}-2\)
=> \(\frac{15}{32}-x=-\frac{5}{4}\)
=> \(x=\frac{15}{32}-\frac{-5}{4}=\frac{15}{32}+\frac{5}{4}=\frac{55}{32}\)
b) \(\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+\frac{x}{30}+\frac{x}{42}+\frac{x}{56}+\frac{x}{72}+\frac{x}{90}=\frac{9}{5}\)
=> \(\frac{x}{1\cdot2}+\frac{x}{2\cdot3}+\frac{x}{3\cdot4}+\frac{x}{4\cdot5}+\frac{x}{5\cdot6}+\frac{x}{6\cdot7}+\frac{x}{7\cdot8}+\frac{x}{8\cdot9}+\frac{x}{9\cdot10}=\frac{9}{5}\)
=> \(\frac{x}{1}-\frac{x}{2}+\frac{x}{2}-\frac{x}{3}+...+\frac{x}{9}-\frac{x}{10}=\frac{9}{5}\)
=> \(\frac{x}{1}-\frac{x}{10}=\frac{9}{5}\)
=> \(\frac{10x-x}{10}=\frac{9}{5}\)
=> \(\frac{9x}{10}=\frac{9}{5}\)
=> \(\frac{9x}{10}=\frac{9\cdot2}{5\cdot2}=\frac{18}{10}\)
=> x = 2
\(\frac{30303}{80808}+\frac{303030}{484848}=1\)
Hk tốt
\(\frac{30303}{80808}+\frac{303030}{484848}\)
\(=\frac{3}{8}+\frac{5}{8}\)
\(=\frac{8}{8}\)
\(=1\)
\(\frac{30303}{80808}+\frac{303030}{484848}\)
\(\frac{30303}{80808}=\frac{30303:10101}{80808:10101}=\frac{3}{8}\)
\(\frac{303030}{484848}=\frac{303030:60606}{484848:60606}=\frac{5}{8}\)
\(\frac{3}{8}+\frac{5}{8}=\frac{3+5}{8}=\frac{8}{8}=1\)
tk mk nha
hihi yêu mọi người nhiều lắm ạ !!!!
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\(\frac{484848}{323232}\)= \(\frac{48}{32}\)= \(\frac{3}{2}\)
\(\frac{3x36}{2x36}\)= \(\frac{108}{72}\)
\(\frac{108:6}{72}\)= \(\frac{18}{72}\)
=> \(\frac{6\text{x}18}{72}\)