Thực hiện phép tính
a ) 3 5 + − 3 4 + 1 20 : 1 2 − 1 2 b ) 1 2 3 : 1 6 + 1 1 4 . 1 2 − 1 5 c ) 0,75 − 13 11 − 50 % : 5 11 d ) 1 27 : − 1 3 2 + 75 % . − 2 2 3
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a.20-\left[30-\left(5-1\right)^2\right]\) \(b.75-\left(3.5^2-4.2^3\right)\)
\(=20-\left[30-4^2\right]\) \(=75-\left(75-4.2^3\right)\)
\(=20-14=6\) \(=75-\left(75-32\right)\)
\(=75-43=32\)
a)\(\left(-3\right).8.\left(-2\right).5=\left(-3\right).\left(-2\right).8.5\)
\(=6.40=240\)
b)\(127-18.\left(5+6\right)=127-18.11\)
\(=127-198=-71\)
c)\(125-\left(-75\right)+32-\left(48+32\right)=125+75+32-48-32\)
\(\left(125+75\right)+\left(32-32\right)-48=200-48=152\)
d)\(3.\left(-4\right).2+2.\left(-5\right)-20=-12.2+2.\left(-5\right)-20\)
\(=\left(-12-5\right).2-20=-17.2-20=-140-20=-160\)
Chúc bạn học tốt
a) - 2 3 .125.32. ( − 76 ) > 0 12.74 . - 3 4 . ( − 395 ) < 0 ⇒ ( − 2 ) 3 .125.32. ( − 76 ) > 12.74. ( − 3 ) 4 . ( − 395 )
b) ( − 1 ) . ( − 2 ) . ( − 3 ) ... ( − 20 ) > 0 ( − 3 ) . ( − 4 ) . ( − 5 ) ... ( − 23 ) < 0 ⇒ ( − 1 ) . ( − 2 ) . ( − 3 ) ... ( − 20 ) > ( − 3 ) . ( − 4 ) . ( − 5 ) ... ( − 23 )
a, (\(\dfrac{9}{10}\) - \(\dfrac{15}{16}\)) \(\times\) ( \(\dfrac{5}{12}\) - \(\dfrac{11}{15}\) - \(\dfrac{7}{20}\))
= (\(\dfrac{72}{80}\) - \(\dfrac{75}{80}\)) \(\times\) (\(\)\(\dfrac{25}{60}\) - \(\dfrac{44}{60}\) - \(\dfrac{21}{60}\))
= - \(\dfrac{3}{80}\) \(\times\) (- \(\dfrac{2}{3}\))
= \(\dfrac{1}{40}\)
b, (-1)3 + (- \(\dfrac{2}{3}\))2 : 2\(\dfrac{2}{3}\) + \(\dfrac{5}{6}\)
= -13 + \(\dfrac{4}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{4}{9}\) \(\times\) \(\dfrac{3}{8}\) + \(\dfrac{5}{6}\)
= -1 + \(\dfrac{1}{6}\) + \(\dfrac{5}{6}\)
= -1 + 1
= 0
Lời giải:
a.
$-18: \frac{3}{5}=-18.\frac{5}{3}=-30$
b.
$\frac{3}{4}:(-9)=\frac{3}{4}.\frac{-1}{9}=\frac{-1}{12}$
c.
$\frac{13}{20}-\frac{6}{7}: \frac{10}{21}=\frac{13}{20}-\frac{6}{7}.\frac{21}{10}$
$=\frac{13}{20}-\frac{9}{5}=\frac{13}{20}-\frac{36}{20}=\frac{-23}{20}$
d.
$\frac{-21}{5}: (\frac{7}{3}.\frac{7}{5})=\frac{-21}{5}: \frac{49}{15}$
$=\frac{-21}{5}.\frac{15}{49}=\frac{-9}{7}$
e.
$(\frac{-2}{5}+\frac{1}{4}): (1-\frac{2}{5})$
$=\frac{-3}{20}: \frac{3}{5}=\frac{-1}{4}$
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
a: =11+3/4-6-5/6+4+1/2+1+2/3
=10+9/12-10/12+6/12+8/12
=10+13/12=133/12
b: \(=2+\dfrac{17}{20}-1-\dfrac{11}{15}+2+\dfrac{3}{20}\)
=3-11/15
=34/15
c: \(=\dfrac{31}{7}:\left(\dfrac{7}{5}\cdot\dfrac{31}{7}\right)\)
\(=\dfrac{31}{7}:\dfrac{31}{5}=\dfrac{5}{7}\)
d: \(=\dfrac{29}{8}\cdot\dfrac{36}{29}\cdot\dfrac{15}{23}\cdot\dfrac{23}{5}=\dfrac{9}{2}\cdot3=\dfrac{27}{2}\)
a: \(2^2\cdot5-\dfrac{\left(1^{10}+8\right)}{3^2}\)
\(=4\cdot5-\dfrac{1+8}{3}\)
=20-3
=17
b: \(5^8:5^6+4\left(3^2-1\right)\)
\(=5^2+4\left(9-1\right)\)
=25+4*8
=25+32
=57
c: \(400-\left\{36-20:\left[3^3-\left(8-3\right)\right]\right\}\)
\(=400-36+20:\left[27-5\right]\)
\(=364+\dfrac{20}{22}\)
\(=364+\dfrac{10}{11}=\dfrac{4014}{11}\)
A) 2².5 - (1¹⁰ + 8) : 3²
= 4.5 - (1 + 8) : 9
= 20 - 9 : 9
= 20 - 1
= 19
B) 5⁸ : 5⁶ + 4.(3² - 1)
= 5² + 4.(9 - 1)
= 25 + 4.8
= 25 + 32
= 57
C) 400 - {36 - 20 : [3³ - (8 - 3)]}
= 400 - [36 - 20 : (27 - 5)]
= 400 -(36 - 20 : 22)
= 400 - (36 - 10/11)
= 400 - 386/11
= 4014/11
a ) − 7 10 b ) 83 8 c ) − 3 4 d ) − 5 3