Tính hợp lý:
a, 4 . 24 . 5 2 - 3 3 . 18 + 3 3 . 12
b, 2 3 . 7 . 5 3 - 5 2 . 65 + 5 2 . 35
c, 2 2 . 74 . 5 2 + 5 2 . 26 . 4 - 7000
d, 55 . 2 2 . 5 + 4 . 89 . 5 2 - 3 2 . 10 3
e, [(315+372).3+(372+315).7]:(26.13+74.13+74)
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a: \(\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)
\(=\left(-\dfrac{5}{6}+\dfrac{2}{5}\right)\cdot\dfrac{8}{3}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right)\cdot\dfrac{8}{3}\)
\(=\dfrac{8}{3}\left(-\dfrac{5}{6}+\dfrac{2}{5}+\dfrac{4}{5}-\dfrac{11}{30}\right)\)
\(=\dfrac{8}{3}\cdot\dfrac{-25+36-11}{30}\)
=0
b: \(\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)
\(=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\cdot\dfrac{7}{3}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right)\cdot\dfrac{7}{3}\)
\(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)\)
\(=\dfrac{7}{3}\cdot0=0\)
c: \(\dfrac{-13}{18}\cdot\dfrac{5}{8}+\dfrac{-5}{18}\cdot\dfrac{2}{9}+\dfrac{-13}{18}\cdot\dfrac{3}{8}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\)
\(=\left(-\dfrac{13}{18}\cdot\dfrac{5}{8}+\dfrac{-13}{18}\cdot\dfrac{3}{8}\right)+\left(-\dfrac{5}{18}\cdot\dfrac{2}{9}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\right)\)
\(=-\dfrac{13}{18}\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{-5}{18}\left(\dfrac{2}{9}+\dfrac{7}{9}\right)\)
\(=-\dfrac{13}{18}-\dfrac{5}{18}=-\dfrac{18}{18}=-1\)
d: Sửa đề: \(\dfrac{-11}{19}\cdot\dfrac{4}{9}+\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-11}{19}\cdot\dfrac{5}{9}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\)
\(=\left(-\dfrac{11}{19}\cdot\dfrac{4}{9}+\dfrac{-11}{19}\cdot\dfrac{5}{9}\right)+\left(\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\right)\)
\(=-\dfrac{11}{19}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\dfrac{-8}{19}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)
\(=-\dfrac{11}{19}-\dfrac{8}{19}=-\dfrac{19}{19}=-1\)
\(a.\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)
\(=\left(-\dfrac{13}{30}\right):\dfrac{3}{8}+\dfrac{13}{30}:\dfrac{3}{8}\)
\(=\left[\left(-\dfrac{13}{30}+\dfrac{13}{30}\right)\right]:\dfrac{3}{8}\)
\(=0:\dfrac{3}{8}=0\)
\(b.\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+-\dfrac{1}{4}\right):\dfrac{3}{7}\)
\(=\left(-\dfrac{7}{20}\right):\dfrac{3}{7}+\dfrac{7}{20}:\dfrac{3}{7}\)
\(=\left[\left(-\dfrac{7}{20}+\dfrac{7}{20}\right)\right]:\dfrac{3}{7}=0:\dfrac{3}{7}=0\)
\(c.-\dfrac{13}{18}.\dfrac{5}{8}+-\dfrac{5}{18}.\dfrac{2}{9}+-\dfrac{13}{18}.\dfrac{3}{8}+-\dfrac{5}{18}.\dfrac{7}{9}\)
\(=\left(\dfrac{5}{8}+\dfrac{3}{8}\right).-\dfrac{13}{18}+\left(\dfrac{2}{9}+\dfrac{7}{9}\right).-\dfrac{5}{18}\)
\(=1.-\dfrac{13}{18}+1.-\dfrac{5}{18}=-\dfrac{13}{18}+-\dfrac{5}{18}=-1\)
\(d.-\dfrac{11}{19}.\dfrac{4}{9}+\dfrac{-8}{19}.\dfrac{3}{7}+-\dfrac{11}{19}.\dfrac{5}{9}+-\dfrac{9}{19}.\dfrac{4}{7}\)
\(=\left(\dfrac{4}{9}+\dfrac{5}{9}\right).-\dfrac{11}{19}+-\dfrac{24}{133}+-\dfrac{36}{133}\)
\(=-\dfrac{11}{19}+-\dfrac{60}{133}=-\dfrac{137}{133}\)
\(a,\dfrac{11}{22}-\dfrac{3}{16}.\dfrac{8}{18}+\dfrac{1}{18}=\dfrac{1}{2}-\dfrac{1}{12}+\dfrac{1}{18}=\dfrac{18}{36}-\dfrac{3}{36}+\dfrac{2}{36}=\dfrac{17}{36}\)
\(b,\dfrac{5}{7}+\dfrac{3}{7}:4-\dfrac{8}{9}.\dfrac{-3}{4}=\dfrac{5}{7}+\dfrac{3}{7}.\dfrac{1}{4}-\dfrac{-2}{3}=\dfrac{5}{7}+\dfrac{3}{28}+\dfrac{2}{3}=\dfrac{60}{84}+\dfrac{9}{84}+\dfrac{56}{84}=\dfrac{125}{84}\)
Bài 3:
a: \(=-8\left(72+19-1\right)=-8\cdot90-720\)
b: \(=-27\left(1011-12-1\right)=-27\cdot998=-26946\)
c: \(=17\cdot\left[29+111\right]+29\cdot\left(-17\right)\)
\(=17\left(29+111-29\right)=17\cdot111=1887\)
d: \(=43\cdot\left(-1\right)+40=-43+40=-3\)
b: \(=128\left(-25-89+89-125\right)=128\cdot\left(-150\right)=-19200\)
5 x 6 = 30 2 x 6 = 12 3 x 6 = 18 4 x 6 = 24
6 x 5 = 30 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24
\(a)\frac{3}{4}+\frac{1}{3}+\frac{2}{5}=\frac{45+20+24}{60}=\frac{89}{60}\)
\(b)\)Rút gọn rồi tính
\(a)\frac{3}{18}+\frac{4}{7}=\frac{1}{6}+\frac{4}{7}=\frac{7+24}{42}=\frac{31}{42}\)
\(b)\frac{12}{24}+\frac{12}{15}=\frac{1}{2}+\frac{4}{5}=\frac{5+8}{10}=\frac{13}{10}\)
Em nến gõ bằng công thức toán học em nhé. Như vậy mọi người nới hiểu đúng đề bài để trợ giúp cho em một cách tốt nhất em ạ!
\(A=2+2^2+2^3+........+2^{100}\)
\(\Leftrightarrow2A=2^2+2^3+.........+2^{100}+2^{101}\)
\(\Leftrightarrow2A-A=\left(2^2+2^3+....+2^{101}\right)-\left(2+2^2+....+2^{100}\right)\)
\(\Leftrightarrow A=2^{101}-2\)
b,c,d tương tự
~ Hok tốt ~
1) \(35.18-5.7.28\)
\(=35.18-35.28\)
\(=35.\left(18-28\right)\)
\(=35.\left(-10\right)\)
\(=-350\)
2) \(45-5.\left(12+9\right)\)
\(=45-60-45\)
\(=\left(45-45\right)-60\)
\(=0-60\)
\(=-60\)
3) \(24.\left(16-5\right)-16.\left(24-5\right)\)
\(=\left(384-120\right)-\left(384-120\right)\)
\(=264-264\)
\(=0\)
4) \(13.\left(23+22\right)-3.\left(17+28\right)\)
\(=13.45-3.45\)
\(=\left(13-3\right).45\)
\(=10.45\)
\(=450\)
tk ủng hộ nha!!!!!!!!1
1/ 35 . 18 - 5 . 7 . 28
= 35 . 18 - 35 . 28
= 35 . (18 - 28)
= 35 . (-10)
= -350
2/ 45 - 5 . (12 + 9)
= 5 . 9 - 5 . 12 + 5 . 9
= 5 . (9 - 12 + 9)
= 5 . 6
= 30
3/ 24 . (16 - 5) - 16 . (24 - 5)
= 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5
= (24 . 16 - 16 . 24) - (24 . 5 - 16 . 5)
= 0 - [5 . (24 - 16)]
= 0 - [5 . 8]
= 0 - 40
= -40
4/ 13 . (23 + 22) - 3 . (17 + 28)
= 13 . 45 - 3 . 45
= 45 . (13 - 3)
= 45 . 10
= 450
a, 4 . 24 . 5 2 - 3 3 . 18 + 3 3 . 12
= 100.24–27.30
= 2400 – 810
= 1590
b, 2 3 . 7 . 5 3 - 5 2 . 65 + 5 2 . 35
= 7.1000 – 25.100
= 7000 – 2500
= 4500
c, 2 2 . 74 . 5 2 + 5 2 . 26 . 4 - 7000
= 100.74 + 100.26 – 70.100
= 100.(74+26–70)
= 100.30
= 3000
d, 55 . 2 2 . 5 + 4 . 89 . 5 2 - 3 2 . 10 3
= 25.4.11 + 4.25.89 – 90.100
= 100.11 + 100.89 – 100.90
= 100.(11+89–90)
= 100.10
= 1000
e, [(315+372).3+(372+315).7]:(26.13+74.13+74)
= [687.3+687.7]:(13.(26+74)+74)
= (687.10):(13.100+74)
= 6870:1374
= 5