a, (- 35) . 48+35.(-52)-(-2 mũ 4)
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a) 2.(-25).(-4).50 = 10000
b) 16.50.(-25).(-250) = 5000000
c)
− 167 . − 83 + 167.17 − 33 = 167.83 + 167.17 − 33 = 167. 83 + 17 − 33 = 167.100 − 33 = 1667
d)
135 − 35 .47 − 53. − 48 − 52 = 100.47 − 53. − 100 = 100.47 + 53.100 = 100. 47 + 53 = 100.100 = 10000
a) 2. − 25 . − 4 .50 = 10000
b) 16.50. − 25 . − 250 = 5000000
c)
− 167 . − 83 + 167.17 − 33 = 167.83 + 167.17 − 33 = 167. 83 + 17 − 33 = 167.100 − 33 = 1667
d)
135 − 35 .47 − 53. − 48 − 52 = 100.47 − 53. − 100 = 100.47 + 53.100 = 100. 47 + 53 = 100.100 = 10000
b: \(=12\left(35\cdot173+27\right)\)
\(=12\cdot6082=72984\)
7: \(=-47\cdot100+53\cdot\left(-100\right)=100\cdot\left(-100\right)=-10000\)
8: \(=30\cdot\left(-4\right)-24\cdot30=30\cdot\left(-28\right)=-840\)
a: \(65\cdot48+35\cdot48+12\cdot58-12\cdot38\)
\(=48\left(65+35\right)+12\left(58-38\right)\)
\(=48\cdot100+12\cdot20\)
\(=4800+240=5040\)
b: \(2018^2+\left\{15^2:\left[175-\left(2^3\cdot5^2-6\cdot25\right)\right]\right\}\)
\(=1+\left\{\dfrac{225}{175-\left(8\cdot25-150\right)}\right\}\)
\(=1+\dfrac{225}{175-\left(200-150\right)}\)
\(=1+\dfrac{225}{175-50}=1+\dfrac{225}{125}=1+\dfrac{5}{3}=\dfrac{8}{3}\)
\(\frac{14^{16}\times21^{32}\times35^{48}}{10^{16}\times35^{32}\times7^{96}}\)
\(=\frac{\left(2\times7\right)^{16}\times\left(3\times7\right)^{32}\times\left(5\times7\right)^{48}}{\left(2\times5\right)^{16}\times\left(5\times7\right)^{32}\times7^{96}}\)
\(=\frac{2^{16}\times7^{16}\times3^{32}\times7^{32}\times5^{48}\times7^{48}}{2^{16}\times5^{16}\times5^{32}\times7^{32}\times7^{96}}=\frac{2^{16}+7^{96}+3^{32}+5^{48}}{2^{16}\times5^{48}\times7^{32}\times7^{96}}\)
\(=\frac{3^{32}}{7^{32}}=\left(\frac{3}{7}\right)^{32}\)
a: Số số hạng là:
(40-2):2+1=20(số)
Tổng là:
\(\dfrac{42\cdot20}{2}=42\cdot10=420\)
a: Số số hạng là:
(40-2):2+1=20(số)
Tổng là:
42x10=420