Tìm số nguyên x, biết:
a) 28 + x = -59
b) x − 4 x 2 − 25 = 0
c) x + 2 = 17
d) − 19 + 4 ( 2 − x ) = 25 − x
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a: \(x\in\left\{0;25\right\}\)
c: \(x\in\left\{0;5\right\}\)
Bài 1: Tìm x biết
a) x - 50 : 25 = 8
x- 2 = 8
x= 8+2
x=10
b) (x + 40).15 = 75.24
x+40 = 75.24:15
x+40 = 70
x= 30
c) (x - 32) - 15 = 0
x- 31 = 15
x= 15+ 31
x = 46
d) 1234 : x = 2
x= 1234:2
x = 617
e) (x - 34).26 = 0
x- 34 = 0: 26
x= 0 + 34
x= 34
f) 152 + (x + 231) : 2 = 358
(x+231):2 = 358- 152
(x+231):2 = 206
x+ 231 = 206*2
x= 412 - 231
x= 181
1.
a) x - 50 : 25 = 8
x - 2 = 8
x = 10
b) (x + 40) . 15 = 75 . 24
x + 40 = 75 . 24 : 15
x + 40 = 120
x = 80
c) (x - 32) - 15 = 0
x - 32 = 15
x = 47
d) 1234 : x = 2
x = 617
e) (x - 34) . 26 = 0
Thỏa mãn điều kiện x - 34 = 0
x = 34
f) 152 + (x + 231) : 2 = 358
(x + 231) : 2 = 206
x + 231 = 412
x = 181
2.
a) 45 . (2 . x - 4) . 13 = 0
Thỏa mãn điều kiện 2 . x - 4 = 0
x = 2
b) 5 . x - 38 : 19 = 13
5 . x - 2 = 13
5 . x = 15
x = 3
c) 100 - 3 . (8 + x) = 1
3 . (8 + x) = 99
8 + x = 33
x = 25
d) [(x + 12) - 17] : 5 = 4
(x + 12) - 17 = 20
x + 12 = 37
x = 25
e) 84 - 4 . (2 . x + 1) = 48
4 . (2 . x + 1) = 36
2 . x + 1 = 9
2 . x = 8
x = 4
a) \(5\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
b) \(25\left(x-4\right)=0\)
\(\Rightarrow x-4=0\)
\(\Rightarrow x=4\)
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
a) 5.(x-7)=0⇔x-7=0⇔x=7
b) 25(x-4)=0⇔x-4=0⇔x=4
c) (34-2x).(2x-6)=0
⇔ 34-2x=0 hoặc 2x-6=0
⇔2x=34 hoặc 2x=6
⇔ x=17 hoặc x=3
d) (2019-x).(3x-12)=0
⇔ 2019-x=0 hoặc 3x-12=0
⇔ x=2019 hoặc x=4
e) 57.(9x-27)=0
⇔ 9x-27=0
⇔ x=3
f) 25+(15-x)=30
⇔ 15-x=5
⇔ x=10
g) 43-(24-x)=20
⇔ 24-x=23
⇔ x=1
h) 2.(x-5)-17=25
⇔ 2(x-5)=42
⇔x-5=21
⇔ x=26
i) 3(x+7)-15=27
⇔ 3(x+7)=42
⇔ x+7=14
⇔ x=7
j) 15+4(x-2)=95
⇔ 4(x-2)=80
⇔ x-2=20
⇔ x=22
k) 20-(x+14)=5
⇔ x+14=15
⇔ x=1
l) 14+3(5-x)=27
⇔ 3(5-x)=13
⇔ 5-x=13/3
⇔ x=5-13/3
⇔ x=2/3
a) \(x+546=46\\ x=46-546\\ x=-500\)
b) \(2x-19\times3=27\\ 2x-57=27\\ 2x=27+57\\ 2x=84\\ x=84:2\\ x=42\)
c) \(x+12=23+3\times3^4\\ x+12=23+3\times81\\ x=23+243-12\\ x=254\)
d) \(x-12=3-3\times2^4\\ x-12=3-3\times16\\ x=3-48+12\\ x=-33\)
e) \(\left(27-x\right)\left(x+9\right)=0\\ \Rightarrow\left[{}\begin{matrix}27-x=0\\x+9=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=27\\x=-9\end{matrix}\right.\)
f) \(\left(-x\right)\left(x-43\right)=0\\ \Rightarrow\left[{}\begin{matrix}-x=0\\x-43=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=43\end{matrix}\right.\)
A) x + 4 = -16
x = -16 - 4
x = -20
Vậy x = -20
b) 12- ( x - 5 ) =5.4
12 -x -5 = 20
x = 7 - 20
x = -13
Vậy x= -13
c) (-2)x - ( x - 17 ) = 34 - ( -x + 25 )
( -2 )x - x + 17 = 34 + x - 25
-3x + 17 = 11 + x
-3x - x = 11 - 17
-4x = -6
x = 1,5
Vậy x = 1,5
d) 17x - ( -16x - 37 ) = 2x + 43
17x + 16x - 2x = 43 -37
30x = 6
x = 0,2
Vậy x = 0,2
a ) 28 + x = − 59 x = − 59 − 28 x = − 87
b ) x − 4 x 2 − 25 = 0 ⇔ x − 4 = 0 x 2 − 25 = 0 ⇔ x = 4 x 2 = 25 ⇔ x = 4 x = ± 5
x + 2 = 17 ⇒ x + 2 = 17 x + 2 = − 17 ⇒ x = 15 x = − 19
d ) − 19 + 4 ( 2 − x ) = 25 − x − 19 + 8 − 4 x = 25 − x 4 x − x = − 19 + 8 − 25 3 x = − 36 = > x = − 12