Kết quả của phép chia 7 x 3 - 7 x + 42 : x 2 - 2 x + 3 là ?
A. - 7x + 14
B. 7x + 14
C. 7x - 14
D. - 7x - 14
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\(a,x-4=11-2x\)
\(x+2x=11+4\)
\(3x=15\)
\(x=5\)
\(b.7x-10=x-28\)
\(7x-x=-28+10\)
\(6x=-18\)
\(x=-3\)
\(c.x-3.x-2=0\)
\(\left(1-3\right).x-2=0\)
\(-2.x-2=0\)
\(-2x=2\)
\(x=-1\)
\(d.|x-5|=10\)
\(\Rightarrow\orbr{\begin{cases}x-5=10\\x-5=-10\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-5\end{cases}}\)
\(e.9-25=\left[7-x\right]-\left[25+7\right]\)
\(-16=\left[7-x\right]-32\)
\(-16+32=7-x\)
\(16=7-x\)
\(x=7-16\)
\(x=-9\)
a: \(x^2\left(x-3\right)-4x+12\)
\(=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)
b: \(2a\left(x+y\right)+x+y=\left(x+y\right)\left(2a+1\right)\)
c: \(6x^2-12x-7x+14\)
\(=6x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(6x-7\right)\)
Tìm x:
\(a.\dfrac{35}{28}-x=\dfrac{5}{14}\\ x=\dfrac{35}{28}-\dfrac{5}{14}\\ x=\dfrac{25}{28}\\ b.\dfrac{6}{7}\times x=\dfrac{2}{3}\\ x=\dfrac{2}{3}:\dfrac{6}{7}\\ x=\dfrac{7}{9}\\ c.x\times7=\dfrac{3}{4}\\ x=\dfrac{3}{4}:7\\ x=\dfrac{3}{28}\\ d.2:x-\dfrac{1}{3}=\dfrac{2}{5}\\ 2:x=\dfrac{2}{5}+\dfrac{1}{3}\\ 2:x=\dfrac{11}{15}\\ x=2:\dfrac{11}{15}\\ x=\dfrac{30}{11}.\)
\(a,\dfrac{35}{28}-x=\dfrac{5}{14}\)
\(x=\dfrac{35}{28}-\dfrac{5}{14}\)
\(x=\dfrac{25}{28}\)
\(b,\dfrac{6}{7}\times x=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}:\dfrac{6}{7}\)
\(x=\dfrac{7}{9}\)
\(c,x\times7=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:7\)
\(x=\dfrac{3}{28}\)
\(d,2:x-\dfrac{1}{3}=\dfrac{2}{5}\)
\(2:x=\dfrac{2}{5}+\dfrac{1}{3}\)
\(2:x=\dfrac{11}{15}\)
\(x=2:\dfrac{11}{15}\)
\(x=\dfrac{30}{11}\)
#YVA
Bài 1:
a)-54
b)-8
Bài 2:
a)(x-14):5=415:413
⇔(x-14):5=42
⇔(x-14):5=16
⇔x-14=80
⇔x=94
b)7x-15x=15-175
⇔-8x=-160
⇔x=20
\(7x\left(2+x\right)-7x\left(x+3\right)=14\)
\(\Leftrightarrow14x+7x^2-7x^2-21x=14\)
\(\Leftrightarrow\left(14x-21x\right)+\left(7x^2-7x^2\right)=14\)
\(\Leftrightarrow-7x+0=14\)
\(\Leftrightarrow-7x=14\)
\(\Leftrightarrow x=14\div\left(-7\right)\)
\(\Leftrightarrow x=-2\)
Vậy x = - 2
Ta có phép chia
Chọn đáp án B.