Tương tự: Tính
a , − 5 − 3 . − 5 + 3 b , 5.4 − 4 . − 8 c , − 10 + 4 . − 6
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a)= 2021.2021-2020.(2021+1)
= 2021.(2020+1)-2020.(2021+1)
= (2021.2020)+2021-(2020.2021)-2020
= 1
b) B= (1+2-3-4)+(5+6-7-8)+(9+10-11-12)...........+(2017+2018-2019-2020)+2021
B= -4+(-4)+....................(-4)+2021
B= -4x505+2021
B= -2020 + 2021
B = 1
bài này dễ mà bạn bạn chỉ cần đổi ra rồi tính bình thường là đc mà
Bài 1:
\(A=2^2\cdot3-4\\ =4\cdot3-4\\ =4\cdot\left(3-1\right)\\ =4\cdot2\\ =8\\ B=16-2^3\cdot2\\ =16-16\\ =0\\ C=4^2-4\cdot2\\ =4\cdot\left(4-2\right)\\ =4\cdot2\\ =8\\ D=3^3-3\cdot3^2\\ =3^3-3^3\\ =0\)
a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}\)
\(=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
b) \(\frac{5^4.20^4}{25^5.4^5}=\frac{\left(20.5\right)^4}{\left(25.4\right)^5}=\frac{100^4}{100^5}=\frac{1}{100}\)
c) \(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.\left(2^{18}+2^8\right)}{2^{12}.\left(1+2^{10}\right)}=\frac{2^{18}+2^8}{1+2^{10}}=256\)
a) a3.a5 = a3+5 = a8
b) x7.x.x4 = x7+1+4 = x12
c) 35.45 = (3.4)5 = 125
d) 85.23 = 25.25.25.23 = 25+5+5+3 = 218
a/a\(^3\).a\(^5\)=a\(^8\)
b/x\(^7\).x.x\(^4\)=x\(^{12}\)
c/3\(^5\).4\(^5\)=2\(^{10}\).3\(^5\)
d/8\(^5\).2\(^3\)=2\(^{18}\)
A = - 522 - { - 222 - [ - 122 - (100 - 522) + 2022] }
A = - 522 - { -222 - [- 122 - 100 + 522 ] + 2022}
A = - 522 - { -222 - { - 222 + 522 } + 2022}
A = - 522 - {- 222 + 222 - 522 + 2022}
A = -522 + 522 - 2022
A = - 2022
B = 1 + \(\dfrac{1}{2}\)(1 + 2) + \(\dfrac{1}{3}\).(1 + 2 + 3) + ... + \(\dfrac{1}{20}\).(1 + 2+ 3 + ... + 20)
B = 1+\(\dfrac{1}{2}\)\(\times\)(1+2)\(\times\)[(2-1):1+1]:2+ ... + \(\dfrac{1}{20}\)\(\times\) (20 + 1)\(\times\)[(20-1):1+1]:2
B = 1 + \(\dfrac{1}{2}\) \(\times\) 3 \(\times\) 2:2 + \(\dfrac{1}{3}\) \(\times\)4 \(\times\) 3 : 2+....+ \(\dfrac{1}{20}\) \(\times\)21 \(\times\) 20 : 2
B = 1 + \(\dfrac{3}{2}\) + \(\dfrac{4}{2}\) + ....+ \(\dfrac{21}{2}\)
B = \(\dfrac{2+3+4+...+21}{2}\)
B = \(\dfrac{\left(21+2\right)\left[\left(21-2\right):1+1\right]:2}{2}\)
B = \(\dfrac{23\times20:2}{2}\)
B = \(\dfrac{23\times10}{2}\)
B = 23
a,[15:(-3)+40:(-8)]-3(16:8)
= ( - 5 - 5 ) - 3. 2
= - 10 - 6
= - 16
b, 3 ( 25 : 5 - 14 : 2 ) - 5 ( 6 : 2 )
= 3 . (5 - 7 ) - 5 . 3
= 3 . - 2 - 5 . 3
= - 21
c, [ - 15 : ( - 3 ) ] - 3 [ 2. ( 5 - 9 : 3 ) ]
= 5 - 3 . 4
= - 7
d, - 2 ( - 3 + 8 : 2 - 7 ) - 5 . 4
= - 2 . - 6 - 5 . 4
= 12 - 20
= - 8
e, 7 . [ - 6 : 2 - 15 : ( - 3 ) - 3 ]
= 7 . ( - 3 + 5 - 3)
= - 7
f, 17 . ( - 84 ) + 17 . ( - 16)
= - 1428 - 272
= - 1700
a,[15:(-3)+40:(-8)]-3(16:8)
= ( - 5 - 5 ) - 3. 2
= - 10 - 6
= - 16
b, 3 ( 25 : 5 - 14 : 2 ) - 5 ( 6 : 2 )
= 3 . (5 - 7 ) - 5 . 3
= 3 . - 2 - 5 . 3
= - 21
c, [ - 15 : ( - 3 ) ] - 3 [ 2. ( 5 - 9 : 3 ) ]
= 5 - 3 . 4
= - 7
d, - 2 ( - 3 + 8 : 2 - 7 ) - 5 . 4
= - 2 . - 6 - 5 . 4
= 12 - 20
= - 8
e, 7 . [ - 6 : 2 - 15 : ( - 3 ) - 3 ]
= 7 . ( - 3 + 5 - 3)
= - 7
f, 17 . ( - 84 ) + 17 . ( - 16)
= - 1428 - 272
= - 1700
a , 16 b , - 128 c , 36