123+5674+4333+111111+23122=?
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\((5674-97)+(97+18-5674)\)
\(=5674-97+97+18-5674\)
\(=(5674-5674)+(-97+97)+18\)
\(=0+0+18\)
\(=18\)
(5674 – 97) – 5674 = 5674 – 97 – 5674
= (5674 – 5674) – 97 = 0 – 97 = -97
3105/4333 là phân số tối giản
Chúc bạn hk tốt
a. (5674 - 97) - 5674
= 5674 - 5674 - 97
= -97
b. (-1075) - (29 - 1075)
= -1075 + 1075 - 29
= -29
a,\(\left(5674-97\right)-5674=5674-97-5674=\left(5674-5674\right)-97=-97\)
b,\(-1075-\left(29-1075\right)=-1075-29+-1075=\left(-1075+1075\right)-29=-29\)c
\(\left(13-135+49\right)-\left(13+49\right)=13-135+49-13-49=-135\)
Nếu thấy mình làm đúng thì tick nha bạn,cảm ơn.
Đặt
\(A=210.\left(\frac{111111}{121212}+\frac{111111}{202020}+\frac{111111}{303030}+\frac{111111}{424242}+\frac{111111}{565656}+\frac{111111}{727272}+\frac{111111}{909090}\right)\)
\(=210.\left(\frac{11}{12}+\frac{11}{20}+\frac{11}{30}+\frac{11}{42}+\frac{11}{56}+\frac{11}{72}+\frac{11}{90}\right)\)
\(=210.11\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\right)\)
\(=2310.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\right)\)
\(=2310.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
\(=2310.\left(\frac{1}{3}-\frac{1}{10}\right)\)
\(=2310.\frac{7}{30}\)
\(=539\)
210.(111111/121212 +111111/202020+11111/303030 + 111111/424242 +111111/565656 +111111/727272 +111111/909090)
= 210 . ( 11/12+11/20+11/42+11/56+11/72+11/90)
= 210.(11.(1/12+1/20+1/42+1/56+1/72+1/90))
=210.(11(1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10))
=210.(11.(1/3-1/10))
=210.(11.7/30)
=210.77/30
=593
T I C K GIÙM MIK
cái này mà toán lớp 3 à
báo cáo nhá
ko nói nhiều
ht
\(\text{123+5674+4333+111111+23122}=\text{144363}\)