Tìm x biết: 3x= 8
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\(\frac{3x}{2.5}+\frac{3x}{5.8}+\frac{3x}{8.11}+\frac{3x}{11.14}=\frac{1}{21}\)
=> \(x\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}\right)=\frac{1}{21}\)
=> \(x\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\right)=\frac{1}{21}\)
=> \(x\left(\frac{1}{2}-\frac{1}{14}\right)=\frac{1}{21}\)
=> \(x.\frac{3}{7}=21\)
=> x = 49
Vậy x = 49
\(3^x+3^{x+1}=3^8.2+2.3^8.2017^0\)
\(3^x+3^x.3=3^8.2^2\)
\(3^x=3^8.2^2:3\)
\(3^x=3^7.2^2\)
3x+3x+1=38.2+2.38.201703x+3x+1=38.2+2.38.20170
3x+3x.3=38.223x+3x.3=38.22
3x=38.22:33x=38.22:3
3x=37.223x=37.22
a) \(x\left(5+3x\right)-\left(x+1\right)\left(3x-2\right)=12\)
\(5x+3x^2-3x^2+2x-3x+2=12\)
\(4x=10\)
\(x=\frac{5}{2}\)
vậy \(x=\frac{5}{2}\)
\(13x\left(x-8\right)-x+8=0\)
\(13x\left(x-8\right)-\left(x-8\right)=0\)
\(\left(13x-1\right)\left(x-8\right)=0\)
\(\Rightarrow\orbr{\begin{cases}13x-1=0\\x-8=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{13}\\x=8\end{cases}}\)
vậy \(\orbr{\begin{cases}x=\frac{1}{13}\\x=8\end{cases}}\)
a,x-(20-3x)=x+7
=>x-20+3x=x+7
=>x-20+3x-x=7
=>x+3x-x=7+20
=>3x=27
=>x=27:3
=>x=9
<=> (3x+2)8 . [ 1 - (3x+2)10 ] = 0
TH1: 3x+2 = 0 <=> x = -2/3
TH2: 3x+2 = 1 => x = -1/3
TH3: 3x+2 = -1 => x = -1
3x+8 = 3(x+2) +2
=> 2 chia hết cho x+2 => x+2 =1;=> x =-1
x+2 =2 => x =0
x+2 =-1 => x =-3
x+2 = -3 => x =-5
x( x + 3) + 3x + 8
\(x\left(x+3\right)+x+2x+8=0\)
\(x\left(x+4\right)+2\left(x+4\right)=0\)
\(\left(x+2\right).\left(x+4\right)=0\)
TH1:
\(x+2=0\)
\(x=0-2\)
\(x=-2\)
TH2:
\(x+4=0\)
\(x=0-4\)
\(x=-4\)
Vậy \(x\in\left\{-2;-4\right\}\)
\(3^x=8\)
\(\Rightarrow log_3\left(3^x\right)=log_38\)
\(\Rightarrow x=log_38=3log_32\)