5.x -7=13
95-3.(x+7)=23
2.x+3^2.3=7^5 : 7^ 2
giúp mình bài này với
ghi đầy đủ nha
Thank
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
( 7 - \(x\))3 + (11 - 7)2 = 141
(7 - \(x\))3 + 42 = 141
( 7 - \(x\))3 + 16 = 141
(7 - \(x\))3 = 141 - 16
( 7 - \(x\))3 = 125
(7 - \(x\))3 = 53
7 - \(x\) = 5
\(x\) = 7 - 5
\(x\) = 2
\(\left(7-x\right)^3+\left(11-7\right)^2=141\)
\(\left(7-x\right)^3+4^2=141\)
\(\left(7-x\right)^3+16=141\)
\(\left(7-x\right)^3=141-16\)
\(\left(7-x\right)^3=125\)
\(\left(7-x\right)=5^3\)
\(\Rightarrow7-x=5\)
\(x=7-5\)
\(x=2\)
\(\text{Vậy x=2}\)
Bài 1
\(\dfrac{1}{2}+\dfrac{7}{10}=\dfrac{5}{10}+\dfrac{7}{10}=\dfrac{12}{10}=\dfrac{6}{5}\)
\(\dfrac{8}{15}\times\dfrac{5}{12}=\dfrac{40}{180}=\dfrac{2}{9}\)
Baì 2
\(30\times\dfrac{5}{3}=50\)
\(\dfrac{6}{5}\times\dfrac{5}{3}=2\)
\(\dfrac{12}{40}\times\dfrac{5}{3}=\dfrac{1}{2}\)
\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
1
\(2.3^x-5=7\)
\(2.3^x\) \(=7-5\)
\(3^x\) \(=2:2\)
\(3^x\) \(=1\)
\(x\) \(=0\)
( 48 x 5 + 48 x 7 - 48 x 12 )
=48 x ( 5 + 7 - 12 )
=48 x 0
= 0
\(\Rightarrow\)( 48 x 5 + 48 x 7 - 48 x 12 ) : ( 1 + 3 + 5 + 7 +.....+ 91 ) = 0
Hk tốt
\(\left(48\text{ x }5+48\text{ x }7-48\text{ x }12\right)\text{ : }\left(1+3+5+7+...+91\right)\)
\(=\left(48\text{ x }5+48\text{ x }7-48\text{ x }12\right)\text{ : }A\)
\(=48\text{ x }\left(5+7-12\right)\text{ : }A\)
\(=48\text{ x }\left(12-12\right)\text{ : }A\)
\(=48\text{ x }0\text{ : }A\)
\(=0\text{ : }A\)
\(=0\)
\(\dfrac{2}{3}:\dfrac{7}{9}\times\dfrac{4}{15}+\dfrac{5}{7}=\dfrac{6}{7}\times\dfrac{4}{15}+\dfrac{5}{7}=\dfrac{8}{35}+\dfrac{5}{7}=\dfrac{33}{35}\)
a) \(\frac{x}{9}=\frac{8}{6}\Rightarrow x=\frac{8}{6}.9=\frac{4}{3}.9=12\)
b) \(\frac{12}{x}=\frac{6}{7}\Rightarrow x=12:\frac{6}{7}=12.\frac{7}{6}=14\)
c) \(5\frac{2}{3}:x=3\frac{2}{3}-2\frac{1}{2}\Rightarrow\frac{17}{3}:x=\left(3-2\right)+\left(\frac{2}{3}-\frac{1}{2}\right)\)
\(\Rightarrow\frac{17}{3}:x=1+\frac{1}{6}=\frac{7}{6}\Rightarrow x=\frac{17}{3}:\frac{7}{6}=\frac{17}{3}.\frac{6}{7}=\frac{34}{7}\)
a: \(\Leftrightarrow5x=20\)
hay x=4
b: \(\Leftrightarrow x+7=24\)
hay x=17
1) \(5x-7=13\Rightarrow5x=13+7=20\Rightarrow x=20:5=4\)
2) \(\Rightarrow3\left(x+7\right)=95-23=72\)
\(\Rightarrow x+7=72:3=24\Rightarrow x=24-7=17\)
3) \(\Rightarrow2x+27=343\Rightarrow2x=343-27=316\Rightarrow x=316:2=158\)