tìm x
x:5=105
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\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
\(x^2\left(x-5\right)+x-5=0\)
\(\Rightarrow x^2\left(x-5\right)+\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x^2-1\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-5=0\\x-1=0\\x+1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x=1\\x=-1\end{matrix}\right.\)
\(x^2\left(x-5\right)+x-5=0\)
\(\Leftrightarrow x-5=0\)
hay x=5
\(x-\dfrac{3}{4}=2\)
\(x=2+\dfrac{3}{4}\)
\(x=\dfrac{11}{4}\)
\(x-\dfrac{5}{15}=\dfrac{42}{105}\)
\(\Rightarrow x=\dfrac{42}{105}+\dfrac{5}{15}\)
\(\Rightarrow x=\dfrac{11}{15}\)
a, 10 - 2 x ( x - 1 ) = 44
2 x ( x - 1 ) = 10 - 44
2 x ( x - 1 ) = -34
x - 1 = -34 : 2
x - 1 = -17
x = -17 + 1
x = -16
Vậy x =-16
b, ( x + 2 ) x 3 - 10 = 5
( x + 2 ) x 3 = 5 + 10
( x + 2 ) x 3 = 15
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
Vậy x = 3
có ai giúp mình ko ạ
x : 5 = 105
<=> x = 105 . 5
<=> x = 525