Tìm X : a,120 = x ² - 1 b, 5 ³ - 5 ( 4 + x ) = 15 c, 4³ - ( x - 2 )² = 52 d, 11³- ˣ - 1 = 120 e, 4 mũ 3x cộng 2 + 8 = 24 f, 3ˣ+³ -3ˣ+1 = 72 h,5ˣ- ¹ + 5ˣ+ ¹ - 2 ² = 646 g, 2ˣ- ¹ + 2ˣ-³ + 3³ jup mik với ạ mik đg cần gấp còn 30p nữa thôi huhu
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a) \(27\cdot75+25\cdot27-150\cdot2023^0\)
\(=27\cdot\left(75+25\right)-150\cdot1\)
\(=27\cdot100-150\)
\(=2700-150\)
\(=2550\)
b) \(3^x+3^{x+1}+16\cdot4=2^2\cdot5^2\)
\(\Rightarrow3^x+3^x\cdot3=100-64\)
\(\Rightarrow3^x\cdot\left(1+3\right)=36\)
\(\Rightarrow3^x\cdot4=36\)
\(\Rightarrow3^x=36:4\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
a) 27.75 + 25.27 - 150.2023⁰
= 27.(75 + 25) - 150.1
= 27.100 - 150
= 2700 - 150
= 2550
b) 3ˣ + 3ˣ⁺¹ + 16.4 = 2².5²
3ˣ.(1 + 3) + 64 = 4.25
3ˣ.4 + 64 = 100
3ˣ.4 = 100 - 64
3ˣ.4 = 36
3ˣ = 36 : 4
3ˣ = 9
3ˣ = 3²
x = 2
1)
a) 2x + 5 = 3⁴ : 3²
2x + 5 = 3²
2x + 5 = 9
2x = 9 - 5
2x = 4
x = 4 : 2
x = 2
b) (3x - 24).73 = 2.74
(3x - 24).73 = 148
3x - 24 = 148/73
3x = 148/73 + 24
3x = 1900/73
x = 1900/73 : 3
x = 1900/219
c) [3.(42 - x)] + 15 = 23.3
126 - 3x + 15 = 69
141 - 3x = 69
3x = 141 - 69
3x = 72
x = 72 : 3
x = 24
d) 126 + (132 - x) = 300
132 - x = 300 - 126
132 - x = 174
x = 132 - 174
x = -42
2)
a) 120 - (x + 55) = 60
x + 55 = 120 - 60
x + 155 = 60
x = 60 - 55
x = 5
b) (7x - 11).3 = 25.52 + 200
(7x - 11).3 = 1500
7x - 11 = 1500 : 3
7x - 11 = 500
7x = 500 + 11
7x = 511
x = 511 : 7
x = 73
c) 2x + 2x + 4 = 544
4x = 544 - 4
4x = 540
x = 540 : 4
x = 135
a) \(\left(x+3\right)^2-\left(x-4\right)\left(x+8\right)=1\)
\(\Leftrightarrow\left(x^2+6x+9\right)-\left(x^2+4x-32\right)-1=0\)
\(\Leftrightarrow2x=-40\)
\(\Rightarrow x=-20\)
b) \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-2\right)\left(x+2\right)=15\)
\(\Leftrightarrow x^3+27-x^3+4x=15\)
\(\Leftrightarrow4x=-12\)
\(\Rightarrow x=-3\)
c) \(\left(x-2\right)^2-\left(x+3\right)^2-4\left(x+1\right)=5\)
\(\Leftrightarrow\left(x^2-4x+4\right)-\left(x^2+6x+9\right)-\left(4x+4\right)=5\)
\(\Leftrightarrow-14x=14\)
\(\Rightarrow x=-1\)
d) \(\left(2x-3\right)\left(2x+3\right)-\left(x-1\right)^2-3x\left(x-5\right)=-44\)
\(\Leftrightarrow4x^2-9-\left(x^2-2x+1\right)-\left(3x^2-15x\right)=-44\)
\(\Leftrightarrow17x=-34\)
\(\Rightarrow x=-2\)
e) \(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=49\)
\(\Leftrightarrow x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=49\)
\(\Leftrightarrow24x=24\)
\(\Rightarrow x=1\)
a) \(120=x^2-1\)
\(\Leftrightarrow x^2=121\)
\(\Rightarrow x=\pm11\)
b) \(5^3-5\left(4+x\right)=15\)
\(\Leftrightarrow25-4-x=3\)
\(\Rightarrow x=18\)
c) \(4^3-\left(x-2\right)^2=52\)
\(\Leftrightarrow\left(x-2\right)^2=12\)
\(\Leftrightarrow\orbr{\begin{cases}x=2-2\sqrt{3}\\x=2+2\sqrt{3}\end{cases}}\)
d) \(11^{3-x}-1=120\)
\(\Leftrightarrow11^{3-x}=121=11^2\)
\(\Rightarrow3-x=2\Rightarrow x=1\)
e) \(4^{3x+2}+8=24\)
\(\Leftrightarrow4^{3x+2}=4^2\)
\(\Rightarrow3x+2=2\Rightarrow x=0\)
f) sửa đề