giải bài này giúp mình\(\frac{x}{8}=\frac{5}{6}\)
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Cách 1
\(8\frac{3}{4}-5\frac{1}{4}=\frac{35}{4}-\frac{21}{4}=\frac{14}{4}=3,5\)
Cách 2
\(8\frac{3}{4}-5\frac{1}{4}=\left(8-5\right)+\left(\frac{3}{4}-\frac{1}{4}\right)=3+\frac{2}{4}=3+0,5=3,5\)
C1:
=35/4-21/4=14/4.
C2:
=(8-5)+(3/4-1/4).
=3+2/4=14/4.
đúng 100000000% .
tkm k nha các bn.
-chúc ai tk mk học giỏi-
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các bạn ơi mình đang cần gấp . Mình chỉ còn 20 phút thui . HUHU
Bài làm :
1) \(\frac{x+11}{4}=\frac{2x+4}{5}\)
\(\Leftrightarrow\left(x+11\right).5=4.\left(2x+4\right)\)
\(\Leftrightarrow5x+55=8x+16\)
\(\Leftrightarrow5x-8x=16-55\)
\(\Leftrightarrow-3x=-39\)
\(\Leftrightarrow x=\frac{-39}{-3}=\frac{39}{3}=13\)
2)\(\frac{x+4}{x+10}=\frac{3}{5}\)
\(\Leftrightarrow\left(x+4\right).5=\left(x+10\right).3\)
\(\Leftrightarrow5x+20=3x+30\)
\(\Leftrightarrow5x-3x=30-20\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=\frac{10}{2}=5\)
3)\(\frac{x+8}{x+14}=\frac{2}{3}\)
\(\Leftrightarrow\left(x+8\right).3=\left(x+14\right).2\)
\(\Leftrightarrow3x+24=2x+28\)
\(\Leftrightarrow3x-2x=28-24\)
\(\Leftrightarrow x=4\)
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\(\frac{1}{3}x-\frac{3}{5}=\frac{5}{6}x+2\)
\(\Leftrightarrow\frac{x}{3}-\frac{3}{5}=\frac{5x}{6}+2\)
\(\Leftrightarrow2x-\frac{18}{5}=5x+12\)
\(\Leftrightarrow2x-5x=\frac{18}{5}+12\)
\(\Leftrightarrow-3x=\frac{78}{5}\)
\(\Leftrightarrow3x=-\frac{78}{5}\)
\(\Leftrightarrow x=-\frac{26}{5}\)
Ps: đoạn nào không hiểu hỏi anh nhé. Nhớ k để tạo động lực cho anh nhé :33
# Aeri #
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Đặt tử A là T ta có:
5T=5(1+5+52+...+59)
5T=5+52+...+510
5T-T=(5+52+...+510)-(1+5+52+...+59)
T=(510-1)/4
Mẫu A là H tính tương tự đc:(59-1)/4.Thay vào ta có:\(A=\frac{\frac{5^{10}-1}{4}}{\frac{5^9-1}{4}}=\frac{5^{10}-1}{5^9-1}\)
B tính tương tự A được \(\frac{3^{10}-1}{3^9-1}\) tới đây sao nx
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\(\Leftrightarrow\left(\frac{3}{4}x-\frac{9}{16}\right)\left(\frac{1}{3}-\frac{3}{5}.\frac{1}{x}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{3}{4}x-\frac{9}{16}=0\\\frac{1}{3}-\frac{3}{5}.\frac{1}{x}=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=\frac{9}{5}\end{cases}}\)
Vậy \(x\in\left\{\frac{3}{4};\frac{9}{5}\right\}\)
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\(8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)=\frac{140}{17}-\left(\frac{23}{9}+\frac{55}{17}\right)=\frac{140}{17}-\frac{886}{153}=\frac{22}{9}=2,444444444444\)
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Ta có:
\(\frac{5}{1\cdot7}+\frac{5}{7\cdot13}+\frac{5}{13\cdot19}+...+\frac{5}{91\cdot97}\)
= \(5\cdot\frac{1}{6}\cdot\left(\frac{6}{1\cdot7}+\frac{6}{7\cdot13}+\frac{6}{13\cdot19}+...+\frac{6}{91\cdot97}\right)\)
= \(\frac{5}{6}\cdot\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+...+\frac{1}{91}-\frac{1}{97}\right)\)
= \(\frac{5}{6}\cdot\left(1-\frac{1}{97}\right)\)
= \(\frac{5}{6}\cdot\frac{96}{97}\)
= \(\frac{80}{97}\)
5/1.7 + 5/7.13 + 5/13.19 + ... + 5/91.97
= 5/6.(1 - 1/7 + 1/7 - 1/13 + 1/13 - 1/19 + ... + 1/91 - 1/97)
= 5/6.(1 - 1/97)
= 5/6.96/97
= 80/97
Ta có : \(\frac{x}{8}=\frac{5}{6}\)
=> \(x\cdot6=5\cdot8\)
=> \(x\cdot6=40\)
=> \(x=\frac{40}{6}=\frac{20}{3}\)
Vậy x = 20/3
\(\frac{x}{8}=\frac{5}{6}\)
\(x\cdot6=8\cdot5\)
\(6x=40\)
\(x=\frac{20}{3}\)