tính nhanh :3876 * 2019 + 2019 * 6123 + 2019
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( - 2019 - 2019 - 2019 - 2019 ) x ( -25 )
= (-4 ) x 2019 x ( - 25 )
= ( -4 ) x ( -25 ) 2019
= 100 x 2019
= 201900
học tốt
(1/2019)^2020 . 2019^2019
= \(\frac{1}{2019^{2020}}\cdot2019^{2019}\)
= \(\frac{2019^{2019}}{2019^{2020}}\)
=1/2019
vậy.......
hok tốt
Trả lời :...............................................
\(\frac{4078379}{4078379}\)
Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
k nhé Kim Râu La
\(\frac{2019}{1\times2}+\frac{2019}{2\times3}+\frac{2019}{3\times4}+...+\frac{2019}{2018\times2019}\)
\(=2019\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{2018\times2019}\right)\)
\(=2019\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2018}-\frac{1}{2019}\right)\)
\(=2019\left(1-\frac{1}{2019}\right)\)
\(=2019\left(\frac{2019}{2019}-\frac{1}{2019}\right)\)
\(=2019\times\frac{2018}{2019}\)\(=\frac{2019\times2018}{2019}=2018\)
a) (4+4)x(2019 +2019 +.....+2019)
= 8 x 125 x 2019
= (8 x 125) x 2019
= 1000 x 2019
= 2019000
b) ( 42+42+...+42)+(125+125+....+125)
= 42 x 125 + 58 x 125
= 125 x ( 42 + 58)
= 125 x 100
= 12500
42+42+...+42)+(125+125+....+125)
= 42 x 125 + 58 x 125
= 125 x ( 42 + 58)
= 125 x 100
= 12500
\(2019\times58+2019\times42+78\)
\(=2019\times\left(58+42\right)+78\)
\(=2019\times100+78\)
\(=201900+78\)
\(=201978\)
\(A=\frac{2019}{2}+\frac{2019}{6}+\frac{2019}{12}+....+\frac{2019}{2018.2019}\)
\(=\frac{2019}{1}.\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{2018.2019}\right)\)
\(=\frac{2019}{1}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2018.2019}\right)\)
\(=\frac{2019}{1}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{4}+....+\frac{1}{2018}-\frac{1}{2019}\right)\)
\(=\frac{2019}{1}.\left(1-\frac{1}{2019}\right)\)
\(=\frac{2019}{1}.\frac{2018}{2019}\)
\(=2018\)
\(A=\frac{2019}{2}+\frac{2019}{6}+\frac{2019}{12}+\frac{2019}{20}+\frac{2019}{30}+\frac{2019}{2018.2019}\)
\(A=\frac{2019}{1.2}+\frac{2019}{2.3}+\frac{2019}{3.4}+\frac{2019}{4.5}+\frac{2019}{5.6}+...+\frac{2019}{2018.2019}\)
\(A=2019.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2018.2019}\right)\)
\(A=2019.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2018}-\frac{1}{2019}\right)\)
\(A=2019.\left(1-\frac{1}{2019}\right)\)\(=2019.\frac{2018}{2019}=2018\)
Vậy A = 2018
-Dấu " . " là dấu nhân.
Sai môn!
\(3876.2019+2019.6123+2019=2019\left(3876+6123+1\right)\)
\(=2019.10000=20190000\)
Bài làm:
Ta có: \(3876.2019+2019.6123+2019\)
\(=2019.\left(3876+6123+1\right)\)
\(=2019.10000\)
\(=20190000\)