Tìm x, biết:
a) ( 3x - 6 ) . 3 = 32
b) x - 7 = -5
c) 123 - 5 . ( x + 4 ) = 38
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a,-4/7=x/21
-12/21 = x/21
x= -12
b,(x-3)/15=1/-5
x - 3 = -1/5 * 15
x - 3 = -3
x = 0
c,.(3x+8)/-12=-5/30
=> 3x + 8 = 2
=> 3x=-6
=>x=-2
123 - 5 . ( x + 4 ) = 38
5 . ( x + 4 ) = 123 - 38
5 . ( x + 4 ) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
( 3x - 24 ) . 73 = 2 . 74
( 3x - 16 ) . 343 = 2 . 2401
( 3x - 16 ) . 343 = 4802
3x - 16 = 4802 : 343
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
123 - 5( x + 4 ) = 38
=> 5( x + 4 ) = 123 - 38
=> x + 4 = 85 ÷ 5
=> x = 17 - 4
=> x = 13
(3x - 24 ) · 73 = 2·74
=> ( 3x - 16 ) = 2 . 74 ÷ 73
=> 3x - 16 = 14
=> 3x = 16 + 14
=> x = 30 ÷ 3
=> x = 10
\(\left[8x-120:4\right]\times3^3=3^6.\)
\(8x-120:4=3^3\)
\(8x-30=27\)
\(8x=27+30\)
\(8x=57\)
\(x=19\)
123 - 5.(x + 4) = 38
123 - 5x - 20 = 38
-5x = 38 - 123 + 20
-5x = -65
x = -65 : -5
x = 13
Vậy x = 13
a,219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1= 119:7
x+1= 17
x= 17-1
x=16
Vậy x=16
b,123-5.(x+40)=38
5.(x+40)=123-38
5.(x+40)=85
x+40= 85:5
x+40=17
x= 17-40
x=-23
Vậy x=-23
c,(3x-6).3=34
3x-6 =34:3
3x-6 =33
3x-6 =27
3x =27+6
3x =33
x =33:3
x =11
Vậy x=11
d, 42.x=39.42-37.42
42.x=1638-1554
42.x=84
x =84:42
x =2
Vậy x=2
Nhớ nhé, học giỏi ^^
a) 123 - 5 (x + 4) = 38
5 (x + 4) = 123 - 38
5 (x + 4) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
b) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
c) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21
\(a,3\left(2x-3\right)+2\left(2-x\right)=-3\\ \Leftrightarrow6x-9+4-2x=-3\\ \Leftrightarrow4x=2\\ \Leftrightarrow x=\dfrac{1}{2}\\ b,x\left(5-2x\right)+2x\left(x-1\right)=13\\ \Leftrightarrow5x-2x^2+2x^2-2x=13\\ \Leftrightarrow3x=13\\ \Leftrightarrow x=\dfrac{13}{3}\\ c,5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\\ \Leftrightarrow5x^2-5x-5x^2-3x+14=6\\ \Leftrightarrow-8x=-8\\ \Leftrightarrow x=1\\ d,3x\left(2x+3\right)-\left(2x+5\right)\left(3x-2\right)=8\\ \Leftrightarrow6x^2+9x-6x^2-11x+10=8\\ \Leftrightarrow-2x=-2\\ \Leftrightarrow x=1\)
\(e,2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\\ \Leftrightarrow10x-16-12x+15=12x-16+11\\ \Leftrightarrow-14x=-4\\ \Leftrightarrow x=\dfrac{2}{7}\\ f,2x\left(6x-2x^2\right)+3x^2\left(x-4\right)=8\\ \Leftrightarrow12x^2-4x^3+3x^3-12x^2=8\\ \Leftrightarrow-x^3-8=0\\ \Leftrightarrow-\left(x^3+8\right)=0\\ \Leftrightarrow-\left(x+2\right)\left(x^2-2x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\left(x^2-2x+4=\left(x-1\right)^2+3>0\right)\end{matrix}\right.\)
Bài 4:
a: Ta có: \(3\left(2x-3\right)-2\left(x-2\right)=-3\)
\(\Leftrightarrow6x-9-2x+4=-3\)
\(\Leftrightarrow4x=2\)
hay \(x=\dfrac{1}{2}\)
b: Ta có: \(x\left(5-2x\right)+2x\left(x-1\right)=13\)
\(\Leftrightarrow5x-2x^2+2x^2-2x=13\)
\(\Leftrightarrow3x=13\)
hay \(x=\dfrac{13}{3}\)
c: Ta có: \(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
\(\Leftrightarrow5x^2-5x-5x^2+7x-10x+14=6\)
\(\Leftrightarrow-8x=-8\)
hay x=1
a)x=3
b)x=2
c)x=13