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a)\(\frac{59^3-41^3}{18}+59.41=\frac{\left(59-41\right)\left(59^2+59.41+41^2\right)}{18}+59.41\)

\(=\frac{18.\left(59^2+59.41+41^2\right)}{18}+59.41=59^2+59.41+41^2+59.41=59^2+2.59.41+41^2=\left(59+41\right)^2=100^2\)

=10000

19 tháng 12 2018

\(a,=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

\(=1+-1\)

\(=0\)

11 tháng 12 2019

a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

                                                     \(=1+\left(-1\right)\)

                                                     \(=0\)

b) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)

                                                                    \(=1+\left(-1\right)+0,5\)

                                                                    \(=0,5\)

_Học tốt nha_

11 tháng 12 2019

a, \(\frac{15}{12}\)\(\frac{5}{13}\)\(\frac{3}{12}\)-\(\frac{18}{13}\)

\(\frac{5}{4}\)\(\frac{5}{13}\) - \(\frac{1}{4}\) - \(\frac{18}{13}\)

\(\left(\frac{5}{4}-\frac{1}{4}\right)\)\(\left(\frac{5}{13}-\frac{18}{13}\right)\)

= 1 - 1 = 0

b, \(\frac{11}{24}\)\(\frac{5}{41}\)\(\frac{13}{24}\)+ 0,5 - \(\frac{36}{41}\)

\(\left(\frac{11}{24}+\frac{13}{24}\right)\)\(\left(\frac{5}{41}+\frac{36}{41}\right)\)+ 0,5

= 1 - 1 + 0,5 = 0,5

c,  \(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)

=\(\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{5}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{5}{11}\)

\(\frac{11}{5}.\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)

\(\frac{11}{5}.\left[\left(-\frac{3}{4}-\frac{1}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)\right]\)

=  \(\frac{11}{5}.\left[\left(-1\right)+1\right]\)

= 0

d, \(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)

\(9.\left(0,75-0,25\right)-2\)

= 9. 0,5 - 2 = 2,5

e, \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)

\(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)

= -1 + 1 - \(\frac{1}{2}\)

\(-\frac{1}{2}\)

12 tháng 12 2019

\(a.=\frac{3}{15}+\frac{-10}{15}\)

\(=-\frac{7}{15}\)

\(b.=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

\(=1+\left(-1\right)\)

\(=0\)

12 tháng 12 2019

\(c.=\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)

\(=-1+1-\frac{1}{2}\)

\(=0-\frac{1}{2}\)

\(=-\frac{1}{2}\)

\(d.=\frac{5}{6}.\left(18\frac{2}{3}-6\frac{2}{3}\right)\)

\(=\frac{5}{6}.12\)

\(=10\)

17 tháng 8 2018

C = 1/3 + -3/4 + 3/5 + 1/57 + -1/36 + 1/15 + -2/9

C = ( 1/3 + 1/57 ) + ( -3/4 + -1/36 ) + ( 3/5 + 1/15 ) + -2/9 

C = ( 19/57 + 1/57 ) + ( -27/36 + -1/36 ) + ( 9/15 + 1/15 ) + -2/9 

C = 20/57 + -28/36 + 10/15 + -2/9 

C = 20/57 + -7/9 + 2/3 + -2/9

C = ( 20/57 + 2/3 ) + ( -7/9 + -2/9 )

C = 58/57 + -1 

C = 1/57

D = 1/2 + -1/5 + -5/7 + 1/6 + -3/35 + 1/3 + 1/41

D = ( 1/2 + 1/3 + 1/6 ) + ( -1/5 + -5/7 +-3/35 ) + 1/41

D = ( 3/6 + 2/6 + 1/6 ) + ( -7/35 + -25/35 + -3/35 ) + 1/41

D = 1 + -1 + 1/41

D = 1/41

E = -1/2 + 3/5 + -1/9 + 1/127 + -7/18 + 4/35 + 2/7 

E = ( -1/2 + -1/9 + -7/18 ) + ( 3/5 + 4/35 ) + 1/127 + 2/7

E = ( -9/18 + -2/18 + -7/18 ) + ( 21/35 + 4/35 ) + 1/127 + 2/7

E = -1 + 5/7 + 1/257 + 2/7 

E = -1 + ( 5/7 + 2/7 ) + 1/127

E = -1 + 1 + 1/127

E = 1/127

17 tháng 8 2018

\(C=\frac{1}{3}+\frac{-3}{4}+\frac{3}{5}+\frac{1}{57}+\frac{-1}{36}+\frac{1}{15}+\frac{-2}{9}.\)

\(C=\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)-\left(\frac{3}{4}+\frac{1}{36}+\frac{2}{9}\right)+\frac{1}{57}\)

\(C=1-1+\frac{1}{57}\)

\(C=\frac{1}{57}\)

18 tháng 7 2019

`1, (10-4-6)+(5/4-9/14-5/7+7/3)

=0+187/84

=187/ 84

18 tháng 7 2019

29/32.41/36-29/32.32/58-41/36.29/32-41/36.18/41

=-29/32.32/58-41/36.18/41

=-1/2-1/2=-1

20 tháng 2 2017

Câu 1 có vế sau = 0

Câu 2 có vế trước = 0

Một biểu thức nhân với 0 thì = 0, nên:

=> kết quả hai bài đều = 0

20 tháng 2 2017

cả 2 câu đều bằng 0

26 tháng 2 2020

Bài 1:

a) \(0,5-\frac{5}{41}+\frac{1}{2}-\frac{36}{41}\)

\(=\frac{1}{2}-\frac{5}{41}+\frac{1}{2}-\frac{36}{41}\)

\(=\left(\frac{1}{2}+\frac{1}{2}\right)-\left(\frac{5}{41}+\frac{36}{41}\right)\)

\(=1-1\)

\(=0.\)

b) \(\left(-\frac{2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(-\frac{1}{3}+\frac{4}{7}\right):\frac{4}{5}\)

\(=-\frac{2}{3}+\frac{3}{7}:\frac{4}{5}-\frac{1}{3}+\frac{4}{7}:\frac{4}{5}\)

\(=\left[\left(-\frac{2}{3}\right)-\frac{1}{3}\right]+\left(\frac{3}{7}+\frac{4}{7}\right):\frac{4}{5}\)

\(=\left(-1\right)+1:\frac{4}{5}\)

\(=\left(-1\right)+\frac{5}{4}\)

\(=\frac{1}{4}.\)

c) \(\left(-\frac{3}{4}\right).\sqrt{\frac{16}{9}+3.\sqrt{49}}\)

\(=\left(-\frac{3}{4}\right).\sqrt{\frac{16}{9}+3.7}\)

\(=\left(-\frac{3}{4}\right).\sqrt{\frac{16}{9}+21}\)

\(=\left(-\frac{3}{4}\right).\sqrt{\frac{205}{9}}\)

\(=\left(-\frac{3}{4}\right).\frac{\sqrt{205}}{3}\)

\(=-\frac{\sqrt{205}}{4}.\)

d) \(\left(-\frac{1}{3}\right)^2.\frac{4}{11}+1\frac{5}{11}.\left(\frac{1}{3}\right)^2\)

\(=\frac{1}{9}.\frac{4}{11}+\frac{16}{11}.\frac{1}{9}\)

\(=\frac{1}{9}.\left(\frac{4}{11}+\frac{16}{11}\right)\)

\(=\frac{1}{9}.\frac{20}{11}\)

\(=\frac{20}{99}.\)

Chúc bạn học tốt!

26 tháng 2 2020

cảm ơn bạn

12 tháng 3 2018

A) \(\frac{2}{3}+\frac{1}{5}-\frac{10}{7}=\frac{13}{15}-\frac{10}{7}=\frac{-59}{105}\)

B) \(\frac{7}{12}-\frac{27}{18}.\frac{2}{18}=\frac{7}{12}-\frac{3}{2}.\frac{2}{18}=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\)

C) \(\left(\frac{23}{41}-\frac{15}{82}\right).\frac{41}{25}=\frac{31}{82}.\frac{41}{25}=\frac{31}{50}\)

D) \(\left(\frac{4}{5}+\frac{1}{2}\right).\left(\frac{3}{13}-\frac{8}{13}\right)=\frac{13}{10}.\frac{-5}{13}=\frac{-1}{2}\)

12 tháng 3 2018

a, = \(\frac{-59}{105}\)

b = \(\frac{7}{144}\)

c= \(\frac{31}{50}\)

d=\(\frac{-1}{2}\)