tìm x (x+3)+(x+7)+...+(x+31)=270
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Bài 2
a: =>x=-23-7=-30
b: =>75:x=15
hay x=5
c: =>2(x+4)=80
=>x+4=40
hay x=36
d: \(\Leftrightarrow2^x\cdot11=88\)
hay x=3
Bài 3:
Có thể chia được nhiều nhất 12 tổ vì UCLN(180;132)=12
Khi đó, mỗi tổ có 15 nam và 11 nữ
a) (x - 15) × 7 - 270 : 45 = 169
(x - 15) × 7 - 6 = 169
(x - 15) × 7 = 169 + 6
(x - 15) × 7 = 175
x - 15 = 175 : 7
x - 15 = 25
x = 25 + 15
x = 40
b) [(4x + 28) × 3 + 55] : 5 = 35
(4x + 28) × 3 + 55 = 35 × 5
(4x + 28) × 3 + 55 = 175
(4x + 28) × 3 = 175 - 55
(4x + 28) × 3 = 120
4x + 28 = 120 : 3
4x + 28 = 40
4x = 40 - 28
4x = 12
x = 12 : 4
x = 3
c) (455 × x : 2 × 6) : 5 = 31
455 × x : 2 × 6 = 31 × 5
455 × x : 2 × 6 = 155
x × 455 : 2 × 6 = 155
x × 1365 = 155
x = 155 : 1365
x = 31/273
d) 128 × x - 12 × x - 16 × x = 520800
(128 - 12 - 16) × x = 520800
100 × x = 520800
x = 520800 : 100
x = 5208
e) (x × 0,25 + 2022) × 2023 = (50 + 2022) × 2023
(x × 0,25 + 2022) × 2023 = 2072 × 2023
(x × 0,25 + 2022) × 2023 = 4191656
x × 0,25 + 2022 = 4191656 : 2023
x × 0,25 + 2022 = 2072
x × 0,25 = 2072 - 2022
x × 0,25 = 50
x = 50 : 0,25
x = 200
f) 4 × x + 100 = x + 280
4 × x - x = 280 - 100
(4 - 1) × x = 180
3 × x = 180
x = 180 : 3
x = 60
g) (x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 7450
x + 1 + x + 2 + x + 3 + ... + x + 100 = 7450
100 × x + 100 × 101 : 2 = 7450
100 × x + 5050 = 7450
100 × x = 7450 - 5050
100 × x = 2400
x = 2400 : 100
x = 24
Tìm x :
x + 1/3 = 4/5
x = 4/5 - 1/3
x = 12/15 - 5/15
x = 7/15
x - 1/2 = 2/7
x = 2/7 + 1/2
x = 4/14 + 7/14
x = 11/14
4/7 × x = 1/3
x = 1/3 : 4/7
x = 1/3 × 7/4
x = 7/12
x : 2/5 = 2/9
x = 2/9 × 2/5
x = 4/45
20 × 7 : ( 5 × x - 3 × 5 ) = 4
140 : 5 × ( x - 3 ) = 4
5 × ( x - 3 ) = 140 : 4
5 × ( x - 3 ) = 35
x - 3 = 35 : 5
x - 3 = 7
x = 7 + 3
x = 10
x - 270 = 420 : 105
x - 270 = 4
x = 4 + 270
x = 274
x - 140 : 35 = 270
x - 4 = 270
x = 270 + 4
x = 274
x + 1/3 = 4/5
x = 4/5 - 1/3
x = 7/15
x - 1/2 = 2/7
x = 2/7 + 1/2
x = 11/14
4/7 * x = 1/3
x = 1/3 : 4/7
x = 7/12
x : 2/5 = 2/9
x = 2/9 * 2/5
x 4 / 45
20 * 7 : ( 5*x - 3 * 5) =4
= 140 :(5*x -3 *5) =4
5*x- 3*5 = 140 : 4
5*x - 3 * 5 = 35
5* x = 35 + 3 * 5
5 * x = 50
x = 50 : 5
x = 10
x - 270 = 402 : 105
x - 270 = 4
x = 270 + 4
x = 274
x- 140 : 35 = 270
x - 4 = 270
x = 270 + 4
x = 274
\(12-x\left(x-7\right)=31-3\left(x+12\right)\)
\(\Leftrightarrow12-x^2+7x=31-3x-36\)
\(\Leftrightarrow12-x^2+7x=-5-3x\)
\(\Leftrightarrow17-x^2+10x=0\)
phương trình bậc 2 lớp 8 mới học :
\(a,\left(-31\right).\left(x+7\right)=0\\ \Rightarrow x+7=0\\ \Rightarrow x=-7\\ b,\left(8-x\right).\left(x+13\right)=0\\ \Rightarrow\left[{}\begin{matrix}8-x=0\\x+13=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=8\\x=-13\end{matrix}\right.\\ c,\left(x^2-25\right)\left(3-x\right)=0\\ \Rightarrow\left(x-5\right)\left(x+5\right)\left(3-x\right)=0\\\Rightarrow \left[{}\begin{matrix}x-5=0\\x+5=0\\3-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\\x=3\end{matrix}\right.\\ d,\left(x-3\right)\left(x^2+4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-3=0\\x^2+4=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x^2=-4\left(loại\right)\end{matrix}\right.\\ \Rightarrow x=3\)
5 x y - 270 = 1365 ( 2 x y + 76 ) x 2 = 432 - 7 x 8
5 x y = 1365 + 270 ( 2 x y + 76 ) x 2 = 432 - 56
5 x y = 1535 ( 2 x y + 76 ) x 2 = 376
y = 1635 : 5 2 x y + 76 = 376 : 2
y = 327 2 x y + 76 = 188
Vậy y = 327 2 x y = 188 - 76
2 x y = 112
y = 112 : 2
y = 56
\(5\times y-270=1365\)
\(\Rightarrow5\times y=1365+270\)
\(\Rightarrow5\times y=1635\)
\(\Rightarrow y=1635:5\)
\(\Rightarrow y=327\)