cho đa thức
A=\(4x^2-5xy+3y^2\)
B=3x\(^2+2xy-y^2\)
tính A+B;A-B
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A + B = ( 4x2 - 5xy + 3y2 ) + ( 3x2 + 2xy - y2 )
= 4x2 - 5xy + 3y2 + 3x2 + 2xy - y2
= 7x2 - 3xy - 2y2
A - B = ( 4x2 - 5xy + 3y2 ) - ( 3x2 + 2xy - y2 )
= 4x2 - 5xy + 3y2 - 3x2 - 2xy + y2
= x2 - 7xy + 4y2
A + B = ( 4x2 - 5xy + 3y2 ) + ( 3x2 + 2xy - y2 )
= 4x2 - 5xy + 3y2 + 3x2 + 2xy - y2
= 7x2 - 3xy + 2y2
A - B = (4x2 - 5xy + 3y2 ) - ( 3x2 + 2xy - y2 )
= 4x2 - 5xy + 3y2 - 3x2 - 2xy + y2
= x2 - 7xy + 4y2
Sửa đề: \(B=3x^2+2xy+y^2\)
\(A+B+C=6x^2+6y^2\)
\(B-C-A=3x^2+2xy+y^2+x^2-3xy-2y^2-4x^2+5xy-3y^2\)
\(=4x^2-xy-y^2-4x^2+5xy-3y^2\)
\(=4xy-4y^2\)
A=(4x^2 - 5xy + 3y^2) + (3x^2 + 2xy + y^2)
=4x^2 - 5xy + 3y^2 + 3x^2 + 2xy + y^2
=(4x2+3x2)+(-5xy+2xy)+(3y2+y2)
=7x2-3xy+4y2
a, A+B+C = ( 4x^2-5xy+3y^2 ) + ( 3x^2+2xy+y^2 ) + ( -x^2+3xy+2y^2 )
= 4x^2-5xy+3y^2 + 3x^2+2xy+y^2 - x^2+3xy+2y^2
= ( 4x^2 + 3x^2 - x^2 ) + ( -5xy + 2xy + 3xy ) + ( 3y^2 + y^2 + 2y^2 )
= 6x^2 + 6y^2
b, B-C-A = ( 3x^2+2xy+y^2 ) - ( -x^2+3xy+2y^2 ) - ( 4x^2-5xy+3y^2 )
= 3x^2+2xy+y^2 + x^2+3xy+2y^2 - 4x^2-5xy+3y^2
= ( 3x^2 + x^2 - 4x^2 ) + ( 2xy + 3xy - 5xy ) + ( y^2 + 2y^2 + 3y^2 )
= 6y^2
c,C-A-B = ( -x^2+3xy+2y^2 ) - ( 4x^2-5xy+3y^2 ) - ( 3x^2+2xy+y^2 )
= -x^2+3xy+2y^2 - 4x^2-5xy+3y^2 - 3x^2+2xy+y^2
= ( -x^2 - 4x^2 - 3x^2 ) + ( 3xy -5xy + 2xy ) + ( 2y^2 + 3y^2 + y^2 )
= -8x^2 + 6y^2
A + B + C = ( 4x2 - 5xy + 3y2 ) + ( 3x2 + 2xy + y2 ) + ( -x2 + 3xy + 2y2 )
= 4x2 - 5xy + 3y2 + 3x2 + 2xy + y2 - x2 + 3xy + 2y2
= ( 4x2 - 3x2 - x2 ) + ( 5xy + 2xy + 3xy ) + ( 3y2 + y2 + 2y2 )
= 10xy + 6y2
B - C - A = ( 3x2 + 2xy + y2 ) - ( -x2 + 3xy + 2y2 ) - ( 4x2 - 5xy + 3y2 )
= 3x2 + 2xy + y2 + x2 - 3xy - 2y2 - 4x2 + 5xy - 3y2
= ( 3x2 + x2 - 4x2 ) - ( 2xy - 3xy + 5xy ) - ( y2 - 2y2 - 3y2 )
= 0 - 0 - ( -4y2 )
= 0 + 4y2
= 4y2
C - A - B = ( -x2 + 3xy + 2y2 ) - ( 4x2 - 5xy + 3y2 ) - ( 3x2 + 2xy + y2 )
= -x2 + 3xy + 2y2 - 4x2 + 5xy - 3y2 - 3x2 - 2xy - y2
= ( -x2 - 4x2 - 3x2 ) - ( 3xy + 5xy - 2xy ) - ( 2y2 - 3y2 - y2 )
= -8x2 - 6xy - ( -2y2 )
= -8x2 - 6xy + 2y2
* Lần đầu làm xD Sai sót gì mong bạn thông cảm *
\(A=4x^2-5xy+3y^2\\\Rightarrow 2A=2\cdot(4x^2-5xy+3y^2)\\\Rightarrow2A=8x^2-10xy+6y^2\\B=3x^2+2xy+y^2\\\Rightarrow3B=3\cdot(3x^2+2xy+y^2)\\\Rightarrow3B=9x^2+6xy+3y^2\\C=-x^2+3xy+2y^2\)
Khi đó: $2A-3B-C$
$=(8x^2-10xy+6y^2)-(9x^2+6xy+3y^2)-(-x^2+3xy+2y^2)$
$=8x^2-10xy+6y^2-9x^2-6xy-3y^2+x^2-3xy-2y^2$
$=(8x^2-9x^2+x^2)+(-10xy-6xy-3xy)+(6y^2-3y^2-2y^2)$
$=-19xy+y^2$
2A-3B-C
\(=2\left(4x^2-5xy+3y^2\right)-3\left(3x^2+2xy+y^2\right)+x^2-3xy-2y^2\)
\(=8x^2-10xy+6y^2-9x^2-6xy-3y^2+x^2-3xy-2y^2\)
\(=-19xy+y^2\)