1,Giải PT sau
\n\na,(x-1)2+(x+3)2=2(x-2)(x+1)+38
\n\nb,5(x2-2x-1)+2(3x-2)=5(x+1)2
\n\nc,(x-3)3-2(x-1)=x(x-2)2-5x2
\n\nd,x(x+3)2-3x=(x+2)3+1
\n\ne,\\(\\frac{\\left(x-1\\right)\\left(x+5\\right)}{3}-\\frac{\\left(x+2\\right)\\left(x+5\\right)}{12}=\\frac{\\left(x-1\\right)\\left(x+2\\right)}{4}\\)
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lỗi j ạ
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