Bài 1:Tính
A,1/7+3+5/6.
B,4/7+5/9+4.
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a,3/7+4/5+4/7.
= ( 3/7 + 4/7 ) + 4/5
= 1 + 4/5
= 9/5
b,6/11+1/3+5/11
= ( 6/11 + 5/11 ) + 1/3
= 1 + 1/3
= 4/3
#hien#
(6 x 5 + 7 - 37) x ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (30 + 7 - 37) x ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0
a) \(x-\frac{4}{9}=\frac{5}{6}\)
\(\Leftrightarrow\frac{18x}{18}-\frac{8}{18}=\frac{15}{18}\)
\(\Rightarrow18x-8=15\)
\(\Leftrightarrow18x=15+8\)
\(\Leftrightarrow18x=23\)
\(\Leftrightarrow x=\frac{23}{18}\)
Vậy \(x=\frac{23}{18}\)
b)\(x-7=\frac{1}{6}\)
\(\Leftrightarrow\frac{6x}{6}-\frac{42}{6}=\frac{1}{6}\)
\(\Rightarrow6x-42=1\)
\(\Leftrightarrow6x=42+1\)
\(\Leftrightarrow6x=43\)
\(\Leftrightarrow x=\frac{43}{6}\)
Vậy \(x=\frac{43}{6}\)
c)\(x-\frac{7}{8}=11\)
\(\Leftrightarrow\frac{8x}{8}-\frac{7}{8}=\frac{88}{8}\)
\(\Rightarrow8x-7=88\)
\(\Leftrightarrow8x=88+7\)
\(\Leftrightarrow8x=95\)
\(\Leftrightarrow x=\frac{95}{8}\)
Vậy \(x=\frac{95}{8}\)
#bn cs thể bỏ\(\Leftrightarrow;\Rightarrow\)đều đc nhé #
#hoktot<3#
a, x - 4/9 = 5/6
x = 5/6 + 4/9
x = 69/54
b, x - 7 = 1/6
x = 1/6 + 7
x = 43/6
c, x - 7/8 = 11
x = 11 + 7/8
x = 95/8
a; 60 \(\times\) (\(\dfrac{7}{12}\) + \(\dfrac{4}{15}\))
= 60 \(\times\) \(\dfrac{7}{12}\) + 60 \(\times\) \(\dfrac{4}{15}\)
= 35 + 16
= 51
\(\frac{2}{6}+\frac{9}{24}\)
\(=\frac{8}{24}+\frac{9}{24}\)
\(=\frac{17}{24}\)
Tương Tự vs các câu còn lại
\(\frac{7}{2}+\frac{1}{3}-\frac{5}{2}\)
\(=\left(\frac{7}{2}-\frac{5}{2}\right)+\frac{1}{3}\)
\(=1+\frac{1}{3}\)
\(=\frac{4}{3}\)
a, MSC : 24
5/8 = 5 x 3/ 8 x 3 = 15/24
7/12 = 7 x 2/ 12 x 2 = 14/24
b, MSC : 60
17/15 = 17 x 4/ 15 x 4 = 68/ 60
29/20 = 29 x 3/ 20 x 3 = 87/ 60
c, MSC : 12
5/6 = 5 x 2/ 6 x 2 = 10/12
3/4 = 3 x 3/ 4 x 3 = 9/12
d, MSC : 84
4/7 = 4 x 12/ 7 x 12 = 48/84
7/12 = 7 x 7/ 12 x 7 = 49/84
cho mik nha!
Mik cảm ơn!
\(A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(\Leftrightarrow A=\frac{1}{1.3}-\frac{1}{11.13}=\frac{1}{3}-\frac{1}{143}=\frac{140}{429}\)
\(A=\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+\frac{4}{7.9.11}+\frac{4}{9.11.13}\)
\(\Rightarrow A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(\Rightarrow A=\frac{1}{1.3}-\frac{1}{11.13}=\frac{1}{3}-\frac{1}{143}=\frac{140}{429}\)
Bài 1:
a, \(\frac{1}{7}+3+\frac{5}{6}=\frac{1}{7}+\frac{3}{1}+\frac{5}{6}=\frac{6}{42}+\frac{126}{42}+\frac{35}{42}=\frac{167}{42}\)
b, \(\frac{4}{7}+\frac{5}{9}+4=\frac{4}{7}+\frac{5}{9}+\frac{4}{1}=\frac{36}{63}+\frac{35}{63}+\frac{252}{63}=\frac{323}{63}\)
A:167/42
B:692/63