Tính dùm mình với
\(-\frac{5^4}{4^4}\)
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a,1/5+4/11+4/5+7/11
=(1/5+4/5)+(4/11+7/11)
=1+1
=2
Chọn B
1367.54+1367.45+1367
=1367.(54+45+1)
=1367.100
=136700
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{50}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{49}{50}\)
\(=\frac{1}{50}\)
Chỗ nào không hiểu nhắn tin cho tớ nha!
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{50}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{49}{50}\)
\(=\frac{1}{50}\)
\(\Rightarrow4:\left(x+9\right)=60\\ \Rightarrow x+9=\dfrac{4}{60}=\dfrac{1}{15}\Rightarrow x=\dfrac{1}{15}-9=-\dfrac{134}{15}\)
\(\frac{1}{2}\left(\frac{3}{2}x+\frac{5}{4}\right)-\frac{1}{3}=\frac{1}{4}\)
\(\frac{1}{2}\left(\frac{3}{2}x+\frac{5}{4}\right)=\frac{1}{4}+\frac{1}{3}\)
\(\frac{1}{2}\left(\frac{3}{2}x+\frac{5}{4}\right)=\frac{7}{12}\)
\(\frac{3}{2}x+\frac{5}{4}=\frac{7}{12}\div\frac{1}{2}\)
\(\frac{3}{2}x+\frac{5}{4}=\frac{7}{6}\)
\(\frac{3}{2}x=\frac{7}{6}-\frac{5}{4}\)
\(\frac{3}{2}x=-\frac{1}{12}\)
\(x=-\frac{1}{12}\div\frac{3}{2}\)
\(x=-\frac{1}{18}\)
\(\frac{x-2}{3}+\frac{x}{2}=\frac{2+x}{4}\)
\(\Leftrightarrow\frac{x-2}{3}.12+\frac{x}{2}.12=\frac{2+x}{4}.12\)
\(\Leftrightarrow4\left(x-2\right)+6x=3\left(x+2\right)\)
\(\Leftrightarrow10x-8=3x+6\)
\(\Leftrightarrow10x=3x+6+8\)
\(\Leftrightarrow10x-3x=3x+14-3x\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=\frac{14}{7}=2\)
=> x = 2
\(\frac{x-5}{x^2-16}+\frac{3}{x+4}=\frac{7}{x-4}\)
\(\Leftrightarrow\frac{x-5}{x^2-16}\left(x+4\right)\left(x-4\right)+\frac{3}{x+4}\left(x+4\right)\left(x-4\right)=\frac{7}{x-4}\left(x+4\right)\left(x-4\right)\)
\(\Leftrightarrow x-5+3\left(x-4\right)=7\left(x+4\right)\)
\(\Leftrightarrow4x-17=7x+28\)
\(\Leftrightarrow4x=7x+28+17\)
\(\Leftrightarrow4x=7x+45\)
\(\Leftrightarrow4x-7x=45\)
\(\Leftrightarrow-3x=45\)
\(\Leftrightarrow x=\frac{45}{-3}=-15\)
=> x = -15
a) (+3).(+9)=27
b) (-3).7=-21
c) 13.(-5)=-65
d) (-150).(-4)=600
e) (+7).(-5)-35
Ta có: \(1\frac{4}{5}+2\frac{5}{7}+3\frac{4}{5}+4\frac{5}{7}\)
\(=\left(1\frac{4}{5}+3\frac{4}{5}\right)+\left(2\frac{5}{7}+4\frac{5}{7}\right)\)
\(=\left(\frac{9}{5}+\frac{19}{5}\right)+\left(\frac{19}{7}+\frac{33}{7}\right)\)
\(=\frac{28}{5}+\frac{52}{7}=13\frac{1}{35}\)
= ( \(1\frac{4}{5}\)+ \(3\frac{4}{5}\)) + ( \(2\frac{5}{7}\)+ \(4\frac{5}{7}\))
= \(4\frac{4}{5}\) + \(6\frac{5}{7}\)
= \(\frac{24}{5}\) + \(\frac{47}{7}\)
= ...... ( tính nốt nhé )
\(-\frac{625}{256}\)nha
\(\frac{-5^4}{4^4}\)=\(\frac{-625}{256}\)