24x-4(2x-3/4)-4(3+2x/2)=36-3(x-3/2)-3(3-2x/3)
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
K
1
23 tháng 7 2022
b: \(\Leftrightarrow32x^5+1-32x^5+1=2\)
=>2=2(luôn đúng)
a: \(\Leftrightarrow\left[\left(x-3\right)^2-\left(x+3\right)^2\right]\left[\left(x-3\right)^2+\left(x+3\right)^2\right]+24x^3=216\)
\(\Leftrightarrow-12x\left(2x^2+18\right)+24x^3=216\)
=>-216x=216
hay x=-1
26 tháng 10 2021
6) ĐKXĐ: \(x\le-6\)
\(\sqrt{\left(x+6\right)^2}=-x-6\Leftrightarrow\left|x+6\right|=-x-6\)
\(\Leftrightarrow x+6=x+6\left(đúng\forall x\right)\)
Vậy \(x\le-6\)
7) ĐKXĐ: \(x\ge\dfrac{2}{3}\)
\(pt\Leftrightarrow\sqrt{\left(3x-2\right)^2}=3x-2\Leftrightarrow\left|3x-2\right|=3x-2\)
\(\Leftrightarrow3x-2=3x-2\left(đúng\forall x\right)\)
Vậy \(x\ge\dfrac{2}{3}\)
8) ĐKXĐ: \(x\ge5\)
\(pt\Leftrightarrow\sqrt{\left(4-3x\right)^2}=2x-10\)\(\Leftrightarrow\left|4-3x\right|=2x-10\)
\(\Leftrightarrow4-3x=10-2x\Leftrightarrow x=-6\left(ktm\right)\Leftrightarrow S=\varnothing\)
9) ĐKXĐ: \(x\ge\dfrac{3}{2}\)
\(pt\Leftrightarrow\sqrt{\left(x-3\right)^2}=2x-3\Leftrightarrow\left|x-3\right|=2x-3\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=2x-3\left(x\ge3\right)\\x-3=3-2x\left(\dfrac{3}{2}\le x< 3\right)\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(ktm\right)\\x=2\left(tm\right)\end{matrix}\right.\)
QB
0
12 tháng 7 2018
Tìm GTNN của biểu thức :
\(x^2+2x+4\)
Đặt A = \(x^2+2x+4\)
\(\Leftrightarrow A=\left(x^2+2.x.1+1\right)+3\)
\(\Leftrightarrow A=\left(x+1\right)^2+3\)
Ta luôn có : \(\left(x+1\right)^2\ge0\forall x\)
Suy ra : \(\left(x+1\right)^2+3\ge3\forall x\)
Hay A\(\ge3\) với mọi x
Dấu "=" xảy ra khi \(x+1=0\Rightarrow x=-1\)
Nên : \(A_{min}=3khix=-1\)
LP
1
TM
17 tháng 12 2016
Câu 1:
\(x^4+5x^3-12x^2+5x+1=x^4+7x^3+x^2-2x^3-14x^2-x+x^2+7x+1\)
\(=\left(x^4+7x^3+x^2\right)-\left(2x^3+14x^2+x\right)+\left(x^2+7x+1\right)\)
\(=x^2\left(x^2+7x+1\right)-2x\left(x^2+7x+1\right)+\left(x^2+7x+1\right)\)
\(=\left(x^2-2x+1\right)\left(x^2+7x+1\right)\)
\(=\left(x-1\right)^2\left(x^2+7x+1\right)\)
Câu 2:
\(\left(x-3\right)\left(x-5\right)\left(x-6\right)\left(x-10\right)-24x^2=x^4-24x^3+203x^2-720x+900-24x^2\)
\(=x^4-24x^3+179x^2-720x+900\)
\(=\left(x^4-7x^3+30x^2\right)-\left(17x^3-119x^2+510x\right)+\left(30x^2-210x+900\right)\)
\(=x^2\left(x^2-7x+30\right)-17x\left(x^2-7x+30\right)+30\left(x^2-7x+30\right)\)
\(=\left(x^2-17x+30\right)\left(x^2-7x+30\right)\)
\(=\left(x^2-2x-15x+30\right)\left(x^2-7x+30\right)\)
\(=\left[x\left(x-2\right)-15\left(x-2\right)\right]\left(x^2-7x+30\right)\)
\(=\left(x-15\right)\left(x-2\right)\left(x^2-7x+30\right)\)
Câu 3:
\(2x^3+11x^2+3x-36=\left(2x^3+14x^2+24x\right)-\left(3x^2+21x+36\right)\)
\(=2x\left(x^2+7x+12\right)-3\left(x^2+7x+12\right)\)
\(=\left(2x-3\right)\left(x^2+7x+12\right)\)
\(=\left(2x-3\right)\left(x^2+3x+4x+12\right)\)
\(=\left(2x-3\right)\left[x\left(x+3\right)+4\left(x+3\right)\right]\)
\(=\left(2x-3\right)\left(x+3\right)\left(x+4\right)\)
16 tháng 6 2023
1: \(=6x^2+2x-15x-5-x^2+6x-9+4x^2+20x+25-27x^3-27x^2-9x-1\)
=-27x^3-18x^2+4x+10
2: =4x^2-1-6x^2-9x+4x+6-x^3+3x^2-3x+1+8x^3+36x^2+54x+27
=7x^3+37x^2+46x+33
5:
\(=25x^2-1-x^3-27-4x^2-16x-16-9x^2+24x-16+\left(2x-5\right)^3\)
\(=8x^3-60x^2+150-125+12x^2-x^3+8x-60\)
=7x^3-48x^2+8x-35
21 tháng 10 2021
Bài 4:
\(x^3-2x^2+x=x\left(x-1\right)^2\)
\(5\left(x-y\right)-y\left(x-y\right)=\left(x-y\right)\left(5-y\right)\)
\(x^2-12x+36=\left(x-6\right)^2\)
\(24x-4\left(2x-\frac{3}{4}\right)-4\left(3+\frac{2x}{2}\right)=36-3\left(x-\frac{3}{2}\right)-3\left(3-\frac{2x}{3}\right)\)
Đề như này đúng không bạn