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-79.(73-27)-73.(-79+27)
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a) -(-1998)-(-271+2998)
=1998+271-2998
=(1998-2998)+271
=-1000+271
=-729
b) -31.25+31.119-31.(-6)
=31.(-25+119+6)
=31.100
=3100
c)-79.(73-27)-73.(-79+27)
=-79.73+79.27+79.73-27.73
=(-79.73+79.73)+(79.27-73.27)
=27(79-73)
=27.6
=162
a, -79(73-27) - 73(-79+27)
= [-79.73 - (-79).27] - [73.(-79) + 73.27]
=-79.73 + 79.27 + 73.79 - 73.27
=79.27-73.27
=27(79-73)
=27.6= 162
b, vì 2n luôn luôn là số chẵn với mọi n thuộc N nên
=> 2n + 1 là số lẻ
ta có:
-52.13.(-2)2.(-1)2n+1
= -25.13.4.(-1)
=25.13.4= 1300
a)
=25 . 13 . 4. (-1) = 100.(-13)=-1300
b)
= -79.73 + 79.27 + 73. 79 - 73. 27
=79. 27 - 73. 27
=27. 6=162
\(\left(-12\right)+\left(-13\right)+36+\left(-11\right)=\left(-12-13-11\right)+36\)
\(=\left(-36\right)+36\)
\(=0\)
a. 111 + (-11 + 27)
= 111 - 11 + 27
= 100 + 27
= 127
b. (27 + 514) - (486 - 73)
= 27 + 514 - 486 + 73
= (27 + 73) + (514 - 486)
= 100 + 28
= 128
c. (36 + 79) + (145 - 79 - 36)
= 36 + 79 + 145 - 79 - 36
= (36 - 36) + (79 - 79) + 145
= 0 + 0 + 145
= 145
a/ = 111+(-11)+27
tự tính
b/ 27+514 - 486+73
tự tính
c/ 36 + 79 + 145 - 79 - 36
tick mk nha bn
a: \(-7264+\left(1543+7264\right)\)
\(=-7264+1543+7264\)
\(=\left(-7264+7264\right)+1543\)
=0+1543
=1543
b: \(\left(144-97\right)-144\)
\(=144-97-144\)
\(=\left(144-144\right)-97\)
=0-97
=-97
c: \(\left(-145\right)-\left(18-145\right)\)
\(=-145-18+145\)
\(=\left(-145+145\right)-18\)
=0-18
=-18
d: \(111+\left(-11+27\right)\)
\(=\left(111-11\right)+27\)
=100+27
=127
e: \(\left(27+514\right)-\left(486-73\right)\)
\(=27+514-486+73\)
\(=\left(27+73\right)+\left(514-486\right)\)
\(=100+28=128\)
f: \(\left(36+79\right)+\left(145-79-36\right)\)
\(=36+79+145-79-36\)
\(=\left(36-36\right)+\left(79-79\right)+145\)
=0+0+145
=145
Ta có :
\(\frac{x-3}{97}+\frac{x-27}{73}+\frac{x-67}{33}+\frac{x-73}{27}=4\)
\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)
\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)
Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}>0\) Nên \(x-100=0\)
\(\Leftrightarrow x=100\)
Vậy \(x=100\)
\(\Leftrightarrow\frac{x-3}{87}+\frac{x-27}{79}+\frac{x-67}{33}+\frac{x-73}{27}-4=0\)
\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)
\(\Leftrightarrow\left(\frac{x-3-97}{97}\right)+\left(\frac{x-27-73}{73}\right)+\left(\frac{x-67-33}{33}\right)+\left(\frac{x-73-27}{27}\right)=0\)
\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)
Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\ne0\)
\(\Rightarrow x-100=0\Leftrightarrow x=100\)
Bài làm :
\(a,53.11+79.101\)
\(=583+7979\)
\(=8562\)
\(b,45.22+55.23\)
\(=9.5.11.2+55.23\)
\(=55.\left(18+23\right)\)
\(=55.41\)
\(=2255\)
\(c,27.332+68.27+73.332+68.73\)
\(=332.\left(27+73\right)+68.\left(27+73\right)\)
\(=\left(332+68\right).\left(27+73\right)\)
\(=400.100\)
\(=40000\)
Học tốt
-79(73-27)-73(-79+27)
=-79.73-(-79).27-73.(-79)-73.27
=-79.73+79.27+73.79-73,27
=(-79.73+73.79)+27(79-73)
=0+27.6
=162