Tìm cặp p/s bằng nhau
8/12,-35/14,88/56,-12/27,11/7,-5/2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các phân số bằng nhau là
\(\frac{8}{18}=\frac{-12}{-27}\)
\(\frac{88}{56}=\frac{11}{7}\)
\(\frac{-35}{14}=\frac{-5}{2}\)
`A)15/9=(5 xx 3)/(3 xx 3)=5/3`
`60/(-96)=(5 xx 12)/(12 xx (-8))=-5/8`
`=>5/3=15/9`
Ta thấy trừ cặp `5/3=15/9` thì còn lại không bằng nhau.
`B)60/(-85)=(5 xx 12)/(5 xx (-17))=-12/17`
`-77/56=(7 xx (-11))/(8 xx 7)=-11/8`
`=>-12/17=60/(-85)`
Ta thấy trừ cặp `-12/17=60/(-85)` thì còn lại không bằng nhau.
a) \(\dfrac{15}{9}=\dfrac{5}{3}\)
b) \(-\dfrac{12}{17}=\dfrac{60}{-85}\)
\(\dfrac{20}{35}\text{=}\dfrac{4}{7}\)
\(\dfrac{5}{15}\text{=}\dfrac{1}{3}\)
\(\dfrac{12}{21}\text{=}\dfrac{4}{7}\)
\(\dfrac{8}{10}\text{=}\dfrac{4}{5}\)
\(\dfrac{20}{30}\text{=}\dfrac{2}{3}\)
\(\Rightarrow\left(\dfrac{20}{35}\text{=}\dfrac{12}{21}\text{=}\dfrac{4}{7}\right);\left(\dfrac{20}{30}\text{=}\dfrac{2}{3}\right).\)
\(\frac{2}{5}=\frac{12}{30}=\frac{40}{100}\)
\(\frac{4}{7}=\frac{12}{21}=\frac{20}{35}\)
\(HokT\)
Bài 1:
a: -8/12<0<-3/-4
b: -56/24<0<7/3
c: 4/25<1<15/13
=>-4/25>-15/13
Bài 2:
a: =-60/45=-4/3
b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6
\(A=\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{8}{11}-\dfrac{5}{7}.\dfrac{2}{11}\)
\(A=\dfrac{5}{7}.\left(\dfrac{5}{11}+\dfrac{8}{11}-\dfrac{2}{11}\right)\)
\(A=\dfrac{5}{7}.\dfrac{5+8-2}{11}\)
\(A=\dfrac{5}{7}.\dfrac{11}{11}\)
\(A=\dfrac{5}{7}.1=\dfrac{5}{7}\)
\(B=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{35}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{63}\)
\(B=\dfrac{95}{72}\)
\(C=\dfrac{4^6.9^5+6^9.120}{8^4-3^{12}-6^{11}}\)
\(C=\dfrac{\left(2^2\right)^3.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
\(C=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(C=\dfrac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.5}\)
\(C=\dfrac{2.6}{5.3}=\dfrac{12}{15}=\dfrac{4}{5}\)
\(\frac{88}{56}\)=\(\frac{11}{7}\)
\(\frac{-35}{14}\)=\(\frac{-12}{27}\)