Tính tổng: S=1-3+3^2-3^3+...-3^99+3^100
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Ta có: \(S=\dfrac{1}{2+\sqrt{2}}+\dfrac{1}{3\sqrt{2}+2\sqrt{3}}+\dfrac{1}{4\sqrt{3}+3\sqrt{4}}+...+\dfrac{1}{100\sqrt{99}+99\sqrt{100}}\)
\(=1-\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{2}}-\dfrac{1}{\sqrt{3}}+...+\dfrac{1}{\sqrt{99}}-\dfrac{1}{10}\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
Ta có: \(S=1-3+3^2-3^3+....+3^{99}-3^{100}\)
\(3S=3-3^2+3^3-3^4+....+3^{100}-3^{101}\)
\(3S+S=\left(3-3^2+3^3-3^4+....+3^{100}-3^{101}\right)+\left(1-3+3^2-3^3+...+3^{99}-3^{100}\right)\)
\(4S=1-3^{100}\)
\(S=\frac{1-3^{100}}{4}\)
tìm x
a) -10-(x-5)+(3-x)=-8
b) 10+3(x-1)=10+6x
c) (x+1)(x-2)=0
S = 1 x 2 + 2 x 3 + ... + 99 x 100
3S = 1 x 2 x 3 + 2 x 3 x (4 - 1) + ..... + 99 x 100 x (101 - 98)
3S = 1 x 2 x 3 + 2 x 3 x 4 - 1 x 2 x 3 + .... + 99 x 100 x 101 - 98 x 99 x 100
3S = 99 x 100 x 101 = 999900
S = 999900 : 3 = 333300
3S=1*2*3+2*3*(4-1)+3*4*(5-2)+.......+99*100*(101-98)
3S=1*2*3+2*3*4-1*2*3+3*4*5-2*3*4+..........+99*100*101-98*99*100
S=99*100*11:3
S=333300
Số số hạng :
(100-1):1+1=100(số hạng)
Tổng bằng:
(100+1)x(100:2)=5050
\(3S=1.2.3+2.3.3+3.4.3+...+99.100.3\)
\(3S=1.2.3.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\left(101-98\right)\)
\(3S=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100\)
\(3S=99.100.101\)
\(S=\frac{99.100.101}{3}\)
\(S=33.100.101\)
S = 1*2+2*3+3*4+...+99*100
3S=1*2(3-0)+2*3(4-1)+3*4(5-2)+...+99*100(101-98)
3S=1*2*3+2*3*4-1*2*3+3*4*5-2*3*4+...+99*100*101-98*99*100
3S=99*100*101
S=(99*100*101):3
S=333 300
S = 1/3 + 1/3^2 + 1/3^3 + 1/3^4 + ... + 1/3^99 + 1/3^100
3S = 1 +1/3 +1/3^2 +1/3^3 + ... + 1/3^98 +1/3^99
3S - S = ( 1 + 1/3 + 1/3^2 +1/^3 + ... + 1/3^98 +1/3^99 ) - ( 1/3 + 1/3^2 + 1/3^3 + 1/3^4 +... + 1/3^99 + 1/3^100 )
2S = 1 - 1/3^100
S = (1 - 1/3^100). 1/2
đây nha:
https://h.vn/hoi-dap/question/87684.html
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