-x+12+52-90=12+52
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a) (x - 78) . 26 = 40
=>x-78 = 40 : 26 = 20/13
=> x = 78 + 20/13
=> x = 1034/13
b) 39 . (x-5) =39
=>x-5=39:39=1
=>x=1+5=6
c) 30- ( 52 - x) =90
=>30-52+x=90
=>-22+x=90
=>x=90-(-22)
=>x=112
d) (x-12) : 5 =2
=>x-12=2.5=10
=>x=10+12=22
\(\text{1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90}\)
\(\text{= 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 + 1/9.1}\)
\(\text{= 1/1 - 1/2 + 1/2 - 1/3 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10}\)
\(=1/1-1/10-10/10-1/10-9/10\)
Vậy \(\text{ 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 = 9/10}\)
Sửa đề:
\(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\)
\(=\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=\dfrac{1}{2}-\dfrac{1}{10}\)
\(=\dfrac{3}{5}\)
a: 7x+58=100
nên 7x=42
hay x=6
c: x-56:x=16
nên x-14=16
hay x=30
c)x - 56 : 4 = 16
x - 56 = 16 : 4
x- 56 = 4
x =4 + 56
x = 60
d)101 + (36 - 4x) = 105
(36- 4x ) = 105 - 101
36 - 4x = 4
4x = 36 - 4
4x = 32
x = 32:4
x = 8
Tham khảo cùng dạng bài toán:
a, (2x−4).(x+3)=0(2x−4).(x+3)=0
TH1:2x−4=0TH1:2x−4=0
2x=4+02x=4+0
2x=42x=4
x=4:2x=4:2
x=2x=2
TH2:x+3=0TH2:x+3=0
x=0+3x=0+3
x=3x=3
Vậy x∈{2;3}
\(\left(-x\right)+\left(-52\right)+\left(-41\right)-\left(-41\right)-\left(-12\right)=-13\\ \Rightarrow\left(-x\right)-52-41+41+12=-13\\ \Rightarrow\left(-x\right)+\left(12-52\right)+\left(41-41\right)=-13\\ \Rightarrow\left(-x\right)+\left(-40\right)=-13\\ \Rightarrow-x=\left(-13\right)-\left(-40\right)\\ \Rightarrow-x=27\\ \Rightarrow x=-27\)
\(=47-\left[\dfrac{\left(45\cdot16-25\cdot12\right)}{14}\right]\)
=47-420/14
=47-30
=17
-x+12+52-90=12+52
-x+(-26)=64
-x=64-(-26)
-x=90
x=90
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