tìm x :
( x + 1233 ) - 1978 = 9876 x : 2: 3 = 138
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(x+1233\right)-1978=9876\)
\(\Leftrightarrow x+1233=9876+1978\)
\(\Leftrightarrow x+1233=11854\)
\(\Leftrightarrow x=11854-1233\)
\(\Leftrightarrow x=10621\)
x : 637 = 2345
=>x= 2345 x 637
=> x =1493765
4000 - x =138
=> x =4000 - 138
=> x = 3862
212552 : x = 326
=>x = 212552 : 326
=> x =652
( x + 1233 ) - 1978 = 9876
=>(x+1233) = 11854
=> x =10621
x : 2 : 3 = 138
=>x:2 = 138 . 3 = 414
=> x = 828
x - 5678 = 9876
x =9876+5678
x =15554
=> chọn ý A . 15554 nhé !!
X x 5 + 1111 = 9876
X x 5 = 9876 - 1111
X x 5 = 8765
x = 8765 : 5
x = 1753
23456+12345=12345+23456
1234+2345=9786-6207
\(23456+12345=12345+x\)
\(=35801\)
\(=35801-12345\)
\(=23456\)
\(1234+2345=9876-x\)
\(=3579\)
\(=9876-3579\)
\(=6297\)
Lời giải:
a. $121-3(x-5)=6$
$3(x-5)=121-6=115$
$x-5=115:3=\frac{115}{3}$
$x=\frac{115}{3}+5=\frac{130}{3}$
b.
$2x-138=2^3.3^2=72$
$2x=72+138=210$
$x=210:2=105$
c.
$x-3\vdots 7$
$\Rightarrow x-3\in\left\{0;7;14;21;28;35;42;49; 56;...\right\}$
Mà $10< x< 50$ nên $x\in\left\{14;21;28;35;42;49\right\}$
d.
$27\vdots x+1$
$\Rightarrow x+1\in\left\{\pm 1; \pm 3; \pm 9; \pm 27\right\}$
$\Rightarrow x\in\left\{0; -2; -4; 2; 8; -10; 26; -28\right\}$
a ) 121-3.(x - 5 ) = 6
3.(x-5) = 121 -6
3. (x-5)=115
x-5 = 115:3
x-5=35
x=35+5
x = 40
b) 2x - 138 = 2'3. 3'2
2x -138=8.9
2x-138=72
2x=72+138
2x=210
x=210:2
x=105
c) theo bài ra : x-3 ∈ B(7)
ta có B(7)=(0,7,14,21,28,35,49,56,...)
=) x-3 ∈ ( 0,7,14,21,28,35,49,56,...)
=) x ∈( 3 , 10,17,24,31,38,42,58,..)
mà 10 <x<50 nên x ∈ ( 17 , 24 ,31,38,42 )
vậy x ∈(17,24,31,38,42)
\(70-5\cdot\left(x-3\right)=45\)
\(\Rightarrow5\cdot\left(x-3\right)=70-45\)
\(\Rightarrow5\cdot\left(x-3\right)=25\)
\(\Rightarrow x-3=\dfrac{25}{5}\)
\(\Rightarrow x-3=5\)
\(\Rightarrow x=5+3=8\)
==============
\(10+2\cdot x=4^5:4^3\)
\(\Rightarrow10+2\cdot x=4^2\)
\(\Rightarrow10+2\cdot x=16\)
\(\Rightarrow2\cdot x=16-10\)
\(\Rightarrow2\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{2}=3\)
=============
\(2\cdot x-138=2^3\cdot3^2\)
\(\Rightarrow2\cdot x-138=72\)
\(\Rightarrow2\cdot x=72+138\)
\(\Rightarrow2\cdot x=210\)
\(\Rightarrow x=\dfrac{210}{2}=105\)
==============
\(231-\left(x-6\right)=1339:12\)
\(\Rightarrow231-x+6=1339:12\)
\(\Rightarrow237-x=\dfrac{1339}{12}\)
\(\Rightarrow x=237-\dfrac{1339}{12}\)
\(\Rightarrow x=\dfrac{1505}{12}\)
( x + 1233 ) - 1978 = 9876
x + 1233 = 9876 + 1978
x + 1233 = 11854
x = 11854 - 1233
x = 10621
Vậy.................................
x : 2 : 3 = 138
x : 2 = 138 . 3
x : 2 = 414
x = 414 . 2
x = 828
Vậy x = 828
x (x+1233) =9876+1978
x (x+1233) =11854-1233
x =10621
x =138 x 3 x 2
x =828