Viết PTHH thực hiện dãy biến đổi sau:
Al → Al2O3 → AlCl3 → Al(OH)3 → Al2O3 → Al
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\(2Al+3O_2\underrightarrow{^{^{t^o}}}2Al_2O_3\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
\(2Al\left(OH\right)_3\underrightarrow{^{^{t^o}}}Al_2O_3+3H_2O\)
\(2NaOH+Al_2O_3\rightarrow2NaAlO_2+H_2O\)
\((1)4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ (2)Al_2O_3+6HCl\to 2AlCl_3+3H_2O\\ (3)AlCl_3+3NaOH\to Al(OH)_3\downarrow +3NaCl\\ (4)2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ (5)2Al_2O_3\xrightarrow{đpnc}4Al+3O_2\)
$(1) 2Al_2O_3 \xrightarrow{đpnc} 4Al + 3O_2$
$2Al + 6HCl \to 2AlCl_3 + 3H_2$
$AlCl_3 + 3KOH \to Al(OH)_3 + 3KCl$
$(2) Fe_2O_3 + 3CO \xrightarrow{t^o} 2Fe + 3CO_2$
$2Fe + 3Cl_2 \xrightarrow{t^o} 2FeCl_3$
$FeCl_3 + 3KOH \to Fe(OH)_3 + 3KCl$
$(3) 2Fe + 3Cl_2 \xrightarrow{t^o} 2FeCl_3$
$FeCl_3 + 3KOH \to Fe(OH)_3 + 3KCl$
$2Fe(OH)_3 \xrightarrow{t^o} Fe_2O_3 + 3H_2O$
$Fe_2O_3 + 3CO \xrightarrow{t^o} 2Fe + 3CO_2$
$Fe + 6H_2SO_4 \to Fe_2(SO_4)_3 + 3SO_2 + 6H_2O$
Dãy biến hóa 1: Al → AlCl3 → Al(OH)3 → Al2O3
Dãy biến hóa 2: AlCl3 → Al(OH)3 → Al2O3 → Al PTHH
dãy biến hóa 1: 1): 2Al + 6HCl → 2AlCl3 + 3H2
(2): AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
(3): 2Al(OH)3 t0 → Al2O3 + 3H2O PTHH
dãy biến hóa 2:
(1): AlCl3 +3NaOH → Al(OH)3+ 3NaCl
(2): 2Al(OH)3 t0 → Al2O3 + 3H2O
(3): 2Al2O3 dpnc → 4Al + 3O2
\(2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+3BaCl_2\to 2AlCl_3+3BaSO_4\downarrow\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow +3NaCl\\ 2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{đpnc}4Al+3O_2\)
\(\left(1\right)2Al_2O_3\xrightarrow[Na_3AlF_6]{đpnc}4Al+3O_2\uparrow\)
\(\left(2\right)2Al+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2\uparrow\)
\(\left(3\right)Al_2\left(SO_4\right)_3+3BaCl_2--->3BaSO_4\downarrow+2AlCl_3\)
\(\left(4\right)AlCl_3+3NaOH--->Al\left(OH\right)_3\downarrow+3NaCl\)
4Al + 3O2 → 2Al2O3
Al2O3 + 6HNO3 → 2Al(NO3)3 + 3H2O
Al(NO3)3 + 3NaOH → Al(OH)3 + 3NaNO3
2Al(OH)3 | → | Al2O3 | + | 3H2O |
Al2O3 + 6HCl → 2AlCl3 + 3H2O
2AlCl3 | → | 2Al | + | 3Cl2 |
(Điện phân trong dung dịch criolit (Na3AlF6))
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a)
+ 4Al + 3O2 =(nhiệt)=> 2Al2O3
+ Al2O3 + 6HNO3 ===> 2Al(NO3)3 + 3H2O
+ Al(NO3)3 + 3NaOH ===> 3NaNO3 + Al(OH)3
+ 2Al(OH)3 =(nhiệt)=> Al2O3 + 3H2O
+ Al2O3 + 6HCl ===> 2AlCl3 + 3H2O
+ 2AlCl3 =(điện phân nóng chảy)=> 2Al + 3Cl2
\(a,2Al_2O_3\rightarrow\left(đpnc,criolit\right)4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(b,2Cu+O_2\rightarrow\left(t^o\right)2CuO\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\)
4Al+3O2--->2Al2O3
Al2O3+6HCl---->2Alcl3+3H2O
AlCl3+3NaOH--->3NaCl+Al(OH)3
2Al(OH)3--->Al2O3+3H2O
Al2O3+3H2--->2Al+3H2O
4Al+3O2-->2Al2O3
Al2O3+6HCl-->2AlCl3+3H2O
AlCl3+3KOH-->3KCl+Al(OH)3
2Al(OH)3-->Al2O3+3H2O
2Al2O3-->4Al+3O2
nhiệt độ nha