Tìm x:
1 + 3 + 5 +...+ 99 = (x-3)2
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cau 1 :
Tu dau bai ta co:
X x 50 + ( 100 + 2 ) x 50 : 2 = 2700
X x 50 + 2550 = 2700
X x 50 = 2700 - 2550
X x 50 = 150
X = 150 : 50
X = 3
Bai 2
1 ) ( 99 + 0 ) x 100 : 2 = 4950
2 ) ( 99 + 1 ) x 99 : 2 = 4950
3 ) day tren co so cac so hang la :
( 99 - 1 ) : 2 + 1 = 50 ( so )
Vay tong la : ( 99 + 1 ) x 50 : 2 = 2500
lik e cho minh nha moi nguoi
1+2+3+4+5+6+7+8+9+...........+99=X+1+2+3+4+5+6+7+8+9+.................+99
4950=4950+X
X=4950-4950
X=0
Xét tổng 1 + 3 +5 +... + 99:
- Số số hạng là: (99-1):2+1= 50 số
- Tổng là: (1 + 99) x 50 : 2 = 2500
Vậy ta có biểu thức:
\(2500=\left(x-2\right)^2\\ \Leftrightarrow50^2=\left(x-2\right)^2\\\Leftrightarrow \left[{}\begin{matrix}x-2=50\\x-2=-50\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=52\\x=-48\end{matrix}\right.\)
Vậy...
\(1+3+5+...+99=\left(x-2\right)^2\)
\(\Rightarrow\left[\left(99-1\right):2+1\right]\left(1+99\right):2=\left(x-2\right)^2\)
\(\Rightarrow50.100:2=\left(x-2\right)^2\)
\(\Rightarrow\left(x-2\right)^2=2500=50^2\)
\(\Rightarrow\left[{}\begin{matrix}x-2=50\\x-2=-50\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=52\\x=-48\end{matrix}\right.\)
1.
\(\left(\frac{3}{1\times3}+\frac{3}{3\times5}+\frac{3}{5\times7}+...+\frac{3}{97\times99}\right)-x:\frac{3}{2}=\frac{7}{3}\\
\left(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{97\times99}\right):\frac{3}{2}-x:\frac{3}{2}=\frac{7}{3}\\\left[\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)-x\right]:\frac{3}{2}=\frac{7}{3}\\
\left(1-\frac{1}{99}\right)-x=\frac{7}{3}\times\frac{3}{2}\\
\frac{98}{99}-x=\frac{7}{2}\\
x=\frac{98}{99}-\frac{7}{2}=\frac{-497}{198}\)
2.\(\frac{x}{y}=\frac{4}{3}\Rightarrow\hept{\begin{cases}x=4a\\y=3a\\x-y=4a-3a=a\end{cases}}\\ \left(x-y\right)^{2015}=5^{2015}\Rightarrow x-y=5\\ \Rightarrow a=5\Rightarrow\hept{\begin{cases}x=4\times5=20\\y=3\times5=15\end{cases}}\)
39.(5 - 2\(x\)) = 39
5 - 2\(x\) = 39 : 39
5 - 2\(x\) = 1
2\(x\) = 5 - 1
2\(x\) = 4
\(x=4:2\)
\(x=2\)
Vậy \(x=2\)
\(\text{1 + 3 + 5 + ... + 99 = (x - 2)}^2\)
\(\text{Số số hạng là:(99-1):2+1=50(số)}\)
\(\Rightarrow\text{(1 + 99) × 50 : 2 = (x - 2)}^2\)
\(\Rightarrow\text{100 × 50 : 2 = (x - 2)}^2\)
\(\text{ x - 2 = 50 hoặc x - 2 = -50}\)
\(\Rightarrow\text{x = 52 hoặc x = -48}\)
1 + 3 + 5 + ... + 99 = ( x - 3 )2
50 số
=> ( 1 + 99 ) x 50 : 2 = ( x - 3 )2
=> 100 x 50 : 2 = ( x - 3 )2
=> 2500 = ( x - 3 )2
=> x - 3 = 50 hoặc x - 3 = -50
=> x = 53 hoặc x = -47