(x^2-9)^2+|y-2|+10
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Trả lời:
7, 5( x + y )2 + 15( x + y )
= 5( x + y )( x + y + 3 )
9, 7x( y - 4 )2 - ( 4 - y )3
= 7x ( 4 - y )2 - ( 4 - y )
= ( 4 - y )2 ( 7x - 4 + y )
11, ( x + 1 )( y - 2 ) - ( 2 - y )2
= ( x + 1 )( y - 2 ) - ( y - 2 )2
= ( y - 2 )( x + 1 - y + 2 )
= ( y - 2 )( x - y + 3 )
8, 9x ( x - y ) - 10 ( y - x )2
= 9x ( x - y ) - 10 ( x - y )2
= ( x - y )[ ( 9x - 10 ( x - y ) ]
= ( x - y )( 9x - 10x + 10y )
= ( x - y )( 10y - x )
10, ( a - b )2 - ( a + b )( b - a )
= ( b - a )2 - ( a + b )( b - a )
= ( b - a )( b - a - a - b )
= - 2a( b - a )
= 2a ( a - b )
12, 2x ( x - 3 ) + y ( x - 3 ) + ( 3 - x )
= 2x ( x - 3 ) + y ( x - 3 ) - ( x - 3 )
= ( x - 3 )( 2x + y - 1 )


a: \(=\left(-1\right)^{10}+\left(-1\right)^9+\left(-1\right)^8+...+\left(-1\right)^2+\left(-1\right)\)
\(=\left(1-1\right)+\left(1-1\right)+...+\left(1-1\right)\)
=0
b: \(=\left(-1\right)^{100}+\left(-1\right)^{99}+...+\left(-1\right)^2+\left(-1\right)\)
\(=\left(1-1\right)+...+\left(1-1\right)\)
=0
c: \(=1^{100}-1^{99}+1^{98}-1^{97}+...+1^2-1\)
=0
f: \(=3\cdot\sqrt{9-5}+7=3\cdot2+7=13\)

1
a )
( 9407 - 7274 ) : y = 8058 : 34
2133 : y = 237
y = 2133 : 237
y = 9
b )
y x 128 - y x 17 - y x 11 = 576000
y x ( 128 - 17 - 11 ) = 576000
y x 100 = 576000
y = 576000 : 100
y = 5760
2
a )
( 125 x 36 ) : ( 5 x 9 ) =
4500 : 45 =
100
b )
1/10 + 2/10 + 3/10 + 4/10 + 5/10 + 6/10 + 7/10 + 8/10 + 9/10=
( 1/10 + 9/10 ) + ( 2/10 + 8/10 ) + ( 3/10 + 7/10 ) + ( 4/10 + 6/ 10 ) + 5/10=
1 + 1 + 1 + 1 + 0,5 =
4,
Chúc bạn học giỏi nhé !

`x+y=8<=>x=8-y`
`=>\sqrt{y^2-16y+64+8}+\sqrt{y^2+9}=10`
`<=>\sqrt{y^2-16y+72}=10-\sqrt{y^2+9}`
ĐK để bp 2 vế:`\sqrt{y^2+9}<=10<=>y^2<=91<=>`$\left[ \begin{array}{l}x \geq \sqrt{91}\\x \leq -\sqrt{91}\end{array} \right.$
`<=>y^2-16y+72=100+y^2+9-20\sqrt{y^2+9}`
`<=>20\sqrt{y^2+9}=16y+37`
ĐKBP:`y>=-37/16`
`<=>400(y^2+9)=196y^2+1369+1184y`
`<=>204y^2-1184y+2231=0`
`<=>y^2-296/51y+2231/204=0`
`\Delta≈(296/51)^2-2231/51`
`≈33,68-4311
`≈-10<0`
`=>` HPT vô nghiệm.
\(\sqrt{x^2+9}+\sqrt{y^2+9}\ge\sqrt{\left(x+y\right)^2+\left(2\sqrt{9}\right)^2}=10\)
Dấu "=" xảy ra khi và chỉ khi \(x=y\)
\(\Rightarrow x=y=4\)
Vậy nghiệm của hệ là \(\left(x;y\right)=\left(4;4\right)\)

a, y \(\times\) \(\dfrac{4}{3}\) = \(\dfrac{16}{9}\)
y = \(\dfrac{16}{9}\) : \(\dfrac{4}{3}\)
y = \(\dfrac{4}{3}\)
b, ( y - \(\dfrac{1}{2}\)) + 0,5 = \(\dfrac{3}{4}\)
y - 0,5 + 0,5 = \(\dfrac{3}{4}\)
y = \(\dfrac{3}{4}\)
c, \(\dfrac{4}{5}-\dfrac{2}{5}y\) = 0,2
0,8 - 0,4y = 0,2
0,4y = 0,8 - 0,2
0,4y = 0,6
y = 1,5
d, (y + \(\dfrac{3}{4}\)) \(\times\) \(\dfrac{5}{7}\) = \(\dfrac{10}{9}\)
y + \(\dfrac{3}{4}\) = \(\dfrac{10}{9}\) : \(\dfrac{5}{7}\)
y + \(\dfrac{3}{4}\) = \(\dfrac{14}{9}\)
y = \(\dfrac{14}{9}\) - \(\dfrac{3}{4}\)
y = \(\dfrac{29}{36}\)
e, y : \(\dfrac{5}{4}\) = \(\dfrac{9}{5}\) + \(\dfrac{1}{2}\)
y : \(\dfrac{5}{4}\) = \(\dfrac{23}{10}\)
y = \(\dfrac{23}{10}\)
y = \(\dfrac{23}{8}\)
f, y \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{3}{2}\) \(\times\) y = \(\dfrac{4}{5}\)
y \(\times\) ( \(\dfrac{1}{2}+\dfrac{3}{2}\)) = \(\dfrac{4}{5}\)
2y = \(\dfrac{4}{5}\)
y = \(\dfrac{2}{5}\)