Tính nhanh:
(-25).21.(-2)2.(-|-3|).(-1)100
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1:
a: x/-2=-18/x
=>x2=36
=>x=6 hoặc x=-6
b: x/2+x/5=17/10
=>7/10x=17/10
hay x=17/7
a: \(=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{18}{21}+\dfrac{3}{21}\right)+\dfrac{19}{32}+\dfrac{13}{32}=1+1+1=3\)
b: \(=35\cdot1.1\cdot25\cdot\left(7,5-7,5\right)=0\)
a: =(34+14)+(1821+321)+1932+1332=1+1+1=3=(43+41)+(2118+213)+3219+3213=1+1+1=3
b: =35⋅1.1⋅25⋅(7,5−7,5)=0=35⋅1.1⋅25⋅(7,5−7,5)=0
1) A=1-2+3-4+5-6+.....+99-100+101?
Giải
A=1-2+3-4+5-6+.....+99-100+101.
Ta viết lại tổng như sau:
A = 101 - 100 + 99 - 98 + ... + 5 - 4 + 3 - 2 + 1
A = 1 + 1 + ... + 1 + 1 + 1
Số phép trừ trong dãy tính là:
( 101 - 1 ) : 2 = 50 ( phép trừ )
Kết quả dãy số là:
1 x 50 + 1 = 51
Vậy:
A=1-2+3-4+5-6+.....+99-100+101.
A= 51
2) B=1+11+21+...+991
=(1+991)+(2+998)+...
=992 x 50
=4960
\(M=\dfrac{3}{1.2}+\dfrac{3}{2.3}+\dfrac{3}{3.4}+...+\dfrac{3}{20.21}\)
\(M=3\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}\right)\)
\(M=3\left(1-\dfrac{1}{21}\right)\)
\(M=3.\dfrac{20}{21}=\dfrac{20}{7}\)
\(N=\dfrac{4}{3}.\dfrac{9}{8}.\dfrac{16}{15}.\dfrac{25}{24}...\dfrac{100}{99}\)
\(N=\dfrac{4.9.16.25...100}{3.8.15.24...99}\)
\(N=\dfrac{2.2.3.3.4.4.5.5...10.10}{1.3.2.4.3.5.4.6...9.11}\)
\(N=\dfrac{2.3.4.5...10}{1.2.3...9}.\dfrac{2.3.4.5...10}{3.4.5...11}\)
\(N=10.\dfrac{2}{11}=\dfrac{20}{11}\)
a) \(M=\dfrac{3}{1.2}+\dfrac{3}{2.3}+\dfrac{3}{3.4}+......+\dfrac{3}{20.21}\)
= \(3.\left(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+......+\dfrac{1}{20}-\dfrac{1}{21}\right)\)
= \(3.\left(\dfrac{1}{1}-\dfrac{1}{21}\right)\)
= \(3.\dfrac{20}{21}\)
= \(\dfrac{20}{7}\)
b) \(N=\dfrac{4}{3}.\dfrac{9}{8}.\dfrac{16}{15}.\dfrac{25}{24}.......\dfrac{100}{99}\)
= \(\dfrac{4.9.16.25.....100}{3.8.15.24.....99}\)
= \(\dfrac{2.2.3.3.4.4.5.5.......10.10}{1.3.2.4.3.5.4.6......9.11}\)
= \(\dfrac{\left(2.3.4.5.....10\right).\left(2.3.4.5.....10\right)}{\left(1.2.3.4......9\right).\left(3.4.5.....11\right)}\)
= \(\dfrac{10.2}{1.11}\)
= \(\dfrac{20}{11}\)
\(53.39+47.39-53.21-47.21\)
\(=39\left(53+47\right)-21\left(53-47\right)\)
\(=39.100-21.6\)
\(=3900-126\)
\(=3774\)
\(b,5.7.77-7.60+49.25-15.42\)
\(=5.7.77-7.5.12+7.7.5.5-3.5.6.7\)
\(=5.7.77-5.7.12+5.7.5.7-5.7.3.6\)
\(=35.77-35.12+35.35-35.18\)
\(=35.\left(77-12+35-18\right)\)
\(=35.82\)
\(=2870\)
= -25 . 21 . 4 . ( -3) . 1
= 25.4 . 21
= 100 . 21
= 2100
\(\left(-25\right).21.\left(-2\right)^2.\left(-|-3|\right).\left(-1\right)^{100}\)
\(=\left(-25\right).21.4.\left(-3\right).1\)
\(=\left(-25.4\right).\left(-3.21\right)\)
\(=-100.\left(-63\right)\)
\(=6300\)
hình như cô làm sai r ạ