B1.Thực hiện phép tính (tính nhanh nếu có thể)
1)195-(2.33 - 100 : 52)
2)-47.43 + (-47).56 + (-47)
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a) 17. 85 + 15 . 17 = 300
= 17. 9 85 = 15) + 300
= 2000
b) 72. 121 + 27 .121 = 121
= 121 . ( 72 + 27 = 1)
= 12100
c) 32. 39 + 52 . 21 - 12 . 39 + 21 . 48
= ( 32 - 12).39 + 21. ( 52 + 48)
= 2880
d) 47 - ( 45.24 - 52.12) : 14
= 47 - ( 45 . 16 - 25.12) : 14
= 17
e) 102 - 60 : ( 54 : 52 - 3. 5)
= 100 - 60 : ( 25 - 15)
= 100 - 6
= 94
\(\left\{\left[65-\left(2^3.9+3^2.8\right):12\right]+47\right\}.5^2+500\)
\(=\left\{\left[65-\left(8.9+9.8\right):12\right]+47\right\}.5^2+500\)
\(=\left\{\left[65-2.9.8:12\right]+47\right\}.5^2+500\)
\(=\left\{\left[65-12\right]+47\right\}.5^2+500\)
\(=\left\{53+47\right\}.5^2+500\)
\(=100.25+500=2500+500=3000\)
a, 10 . 27 - 27 : 9
= 270 - 3
= 263
b, 72 . 33 + 72 . 67
= 72 ( 33 + 67 )
= 72 . 100
= 49 . 100
= 4900
c, 490 - [ ( 128 + 22 ) : 3 . 22 ] - 7
= 490 - ( 150 : 3 . 4 ) - 7
= 490 - ( 50 . 4 ) - 7
= 490 - 200 - 7
= 290 - 7
= 283
a ) 1 12 + 2 3 + − 3 4 = 1 12 + 8 12 + − 9 12 = 0
b ) 1 2 − 2 5 + − 7 10 = 5 10 − 4 10 + − 7 10 = − 6 10 = − 3 5 c ) 1 2 + − 3 7 + 5 2 + − 4 7 = 1 2 + 5 2 + − 3 7 + − 4 7 = 2 d ) 9 8 − 4 7 + − 1 8 + 11 7 = 9 8 + − 1 8 + − 4 7 + 11 7 = 2 e ) 6 11 + − 2 3 + 5 11 = 6 11 + 5 11 + − 2 3 = 1 3 f ) − 1 2 + 11 4 − 11 4 − 1 2 = − 1 2 + 11 4 − 11 4 + 1 2 = 0
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1) 195-(2.3\(^3\) - 100 : 5\(^2\))
= 195-(2.27 - 100 : 25)
= 195-(54 - 4)
= 195-50
= 145
2) -47.43 + (-47).56 + (-47)
= -47.43 + (-47).56 + (-47).1
= -47.(43+56+1)
= -47.100
= -4700
1) Ta có: \(195-\left(2\cdot3^3-\frac{100}{5^2}\right)\)
\(=195-\left(54-4\right)=195-50=145\)
2) Ta có: \(-47\cdot43+\left(-47\right)\cdot56+\left(-47\right)\)
\(=-47\left(43+56+1\right)=-47\cdot100=-4700\)