Giúp mình với
Khai triển
A) (2x – y)³
b) 27x³ + 1
c) (2x)³ - 125
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a: \(\left(3x+y\right)\left(9x^2-3xy+y^2\right)=27x^3+y^3\)
b: \(\left(2x-5\right)\left(4x^2+10x+25\right)=8x^3-125\)
a) (3x+y)(9x2-3xy+y2) = 27x3+y3
b)(2x-5)(4x2+10x+25) = 8x3-125
a)(3x+y)(9x2 -3xy+y2 )=27x3 +y3 |
b)(2x-5)(4x2 +10x+52 )=8x3 -125 |
nho | k |
minh | nhe |
a: \(\left(x^2+2y\right)^3\)
\(=\left(x^2\right)^3+3\cdot\left(x^2\right)^2\cdot2y+3\cdot x^2\cdot\left(2y\right)^2+\left(2y\right)^3\)
\(=x^6+6x^4y+12x^2y^2+8y^3\)
b: \(\left(\dfrac{1}{2}x-1\right)^3\)
\(=\left(\dfrac{1}{2}x\right)^3-3\cdot\left(\dfrac{1}{2}x\right)^2\cdot1+3\cdot\dfrac{1}{2}x\cdot1^2-1^3\)
\(=\dfrac{1}{8}x^3-\dfrac{3}{4}x^2+\dfrac{3}{2}x-1\)
a: =(6x)^2-(3x-2)^2
=(6x-3x+2)(6x+3x-2)
=(9x-2)(3x+2)
d: \(=\left[\left(x+1\right)^2-\left(x-1\right)^2\right]\left[\left(x+1\right)^2+\left(x-1\right)^2\right]\)
\(=4x\cdot\left[x^2+2x+1+x^2-2x+1\right]\)
=8x(x^2+1)
e: =(4x)^2-2*4x*3y+(3y)^2
=(4x-3y)^2
f: \(=-\left(\dfrac{1}{4}x^4-2\cdot\dfrac{1}{2}x^2\cdot2y^3+4y^6\right)\)
\(=-\left(\dfrac{1}{2}x^2-2y^3\right)^2\)
g: =(4x)^3+1^3
=(4x+1)(16x^2-4x+1)
k: =x^3(27x^3-8)
=x^3(3x-2)(9x^2+6x+4)
l: =(x^3-y^3)(x^3+y^3)
=(x-y)(x+y)(x^2-xy+y^2)(x^2+xy+y^2)
a) Ta có: 27\(x^3\)+ y\(^3\) = (3x)\(^3\) + y\(^3\)= (3x + y)[(3x)\(^2\) – 3x . y + y\(^2\)] = (3x + y)(9x\(^2\) – 3xy + y\(^2\))
Nên: (3x + y) (9x\(^2\) – 3xy + y\(^2\)) = 27x\(^3\) + y\(^3\)
b) Ta có: 8x\(^3\) – 125 = (2x)\(^3\) – 53= (2x – 5)[(2x)\(^2\) + 2x . 5 + 5\(^2\)]
= (2x – 5)(4x\(^2\) + 10x + 25)
Nên:(2x – 5)(4x\(^2\) + 10x + 25)= 8x\(^3\) – 125
Trả lời:
a) Ta có:
27x3 + y3 = (3x)3 + y3= (3x + y)[(3x)2 – 3x . y + y2] = (3x + y)(9x2 – 3xy + y2)
Nên: (3x + y) (9x2 – 3xy + y2 ) = 27x3 + y3
b) Ta có:8x3 - 125 = (2x)3 - 53= (2x - 5)[(2x)2 + 2x . 5 + 52]
= (2x - 5)(4x2 + 10x + 25)
Nên: (2x - 5)(4x2+ 10x +25 ) = 8x3 - 125
Lời giải:
a. $=(2x)^2-2.2x.5y+(5y)^2=4x^2-20xy+25y^2$
b. $=(3x)^2+2.3x.2y+(2y)^2=9x^2+12xy+4y^2$
c. $=(4y+3x)(4y-3x)=(4y)^2-(3x)^2=16y^2-9x^2$
A)\(8x^3\)\(-\)\(12x^2y\)\(+\)\(6xy^2\)\(-y^3\)
B)\(\left(3x+1\right)\left(9x^2-3x+1\right)\)
C)\(\left(2x-5\right)\left(4x^2+10x+25\right)\)