tìm x
/x+5/=6
giúp mk với ạ
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a) 11 - 3(2x - 1) = -8x + 5
⇔ 11 - 6x + 3 = -8x + 5
⇔ -6x + 8x = 5 - 11 - 3
⇔ 2x = -9
⇔ x = -9/2
Vậy S = {-9/2}
b) (x - 3)/5 + (1 + 2x)/3 = 6
⇔ 3(x - 3) + 5(1 + 2x) = 6.15
⇔ 3x - 9 + 5 + 10x = 90
⇔ 13x = 90 + 9 - 5
⇔ 13x = 94
⇔ x = 94/13
Vậy S = {94/13}
\(\Rightarrow\dfrac{2x}{6}=\dfrac{3y}{6}=\dfrac{z}{6}\Rightarrow\dfrac{x}{3}=\dfrac{y}{2}=\dfrac{z}{6}=\dfrac{x+y+z}{3+2+6}=\dfrac{11}{11}=1\\ \Rightarrow\left\{{}\begin{matrix}x=3\\y=2\\z=6\end{matrix}\right.\Rightarrow z-x=6-3=3\left(A\right)\)
\(a,\dfrac{3}{4}:\dfrac{6}{x}=\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{4}:\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{5}\\ x=6:\dfrac{3}{5}\\ x=10\\ b,\left(x+\dfrac{7}{4}\right)\times\dfrac{2}{3}=6\\ x+\dfrac{7}{4}=6:\dfrac{2}{3}\\x+\dfrac{7}{4}=9\\ x=9-\dfrac{7}{4}\\ x=\dfrac{29}{4}\)
\(ƯC\left(18,54\right)=Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\\ \Rightarrow x\in\left\{9;18\right\}\)
\(\left(y-\dfrac{2}{3}\right):\dfrac{4}{5}=\dfrac{5}{6}\)
\(y-\dfrac{2}{3}=\dfrac{5}{6}\times\dfrac{4}{5}\)
\(y-\dfrac{2}{3}=\dfrac{2}{3}\)
\(y=\dfrac{2}{3}+\dfrac{2}{3}\)
\(y=\dfrac{4}{3}\)
\(x\times\dfrac{3}{5}=\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}:\dfrac{3}{5}=\dfrac{25}{18}\)
x = 6 - 5
x = 1