a)9.5+8.10-27
b)36:9+100-27.3
c)29-[16+3.(51-49)]
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f: \(-20:2^2+\left(-5\right)^9:5^8\)
\(=-20:4-5^9:5^8\)
=-5-5
=-10
g: \(-100:5^2+\left(-7\right)\cdot\left(-3\right)^2\)
\(=-\dfrac{100}{25}-7\cdot9\)
=-4-63
=-67
h: \(-84:4+3^9:\left(-3\right)^7+\left(-5\right)^0\)
\(=-21-3^9:3^7+1\)
\(=-21-3^2+1\)
=-20-9
=-29
i: \(-29-\left[16+3\left(51-49\right)\right]\)
\(=-29-16-3\cdot2\)
=-45-6
=-51
j: \(-58\cdot75+58\cdot\left(-50\right)-58\left(-25\right)\)
\(=58\cdot\left(-75\right)+58\left(-50\right)+58\cdot25\)
\(=58\left(-75-50+25\right)\)
\(=-58\cdot100=-5800\)
a)100:25+7.9=4+16=20
b)84:4+9+1=31
c)29-(16+3.1)=10
d)5.4+98:49=20+2=22
\(a,=75+60-13=122\\ b,=250-25+40=265\\ c,=4+100-9=95\\ d,=45+80-27=98\\ e,=5^3-100=125-100=25\\ g,=5+5=10\)
59 + 64 = 36 + 63 + 59 _Sai_
129 + 157 - 29 =129 - 29 + 157 _Đúng_
129 + 157 - 29 = 157 + 129 - 29 _Đúng_
4 +16 x 25 = 16 + 4 x 25 _Sai_
21 + 49 : 7 = 49 + 21 : 7 _Sai_
(36 + 45 ) : 9 = (45+36 ) : 9 _Đúng_
(Cái này tính nhẩm là ra thôi bạn ạ! Đúng cho mình 1 tick nhé bạn!)
\(29-\left[16+3.\left(51-49\right)\right]\)
\(=29-\left[16+3.2\right]\)
\(=29-\left[16+6\right]\)
\(=29-22=7\)
`@` `\text {Ans}`
`\downarrow`
`29 - [16 + 3.(51 - 49)]`
`= 29 - (16 + 3.2)`
`= 29 - (16 + 6)`
`= 29 - 22`
`= 7`
29 – [16 + 3.(51 – 49)]
= 29 - [16 + 3. 2]
= 29 - [16 + 6]
= 29 - 22
= 7
\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
\(a,9.5+8.10-27\)
\(=45+80-27\)
\(=125-27\)
\(=98\)
\(b,36:9+100-27.3\)
\(=4+100-81\)
\(=104-81\)
\(=23\)
\(c,29-\left[16+3.\left(51-49\right)\right]\)
\(=29-\left[16+3.2\right]\)
\(=29-\left[16+6\right]\)
\(=29-22\)
\(=7\)