142 - [ 50 - ( 2 mũ 3 . 10 - 2.5 ) ]
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\(142-\left[50-\left(2^3×10-2^3×5\right)\right]\)
\(=142-\left[50-\left(8×10-8×5\right)\right]\)
\(=142-\left[50-\left(80-40\right)\right]\)
\(=142-\left[50-40\right]\)
\(=142-10\)
\(=132\)
142-[50-(8 x 10 - 8 x5)]
142-{50-[8 x(10-5)}
142-{50-8 x 5}
142-{50-40}
142-10
132
33 : 313 + 50 : 52 = 3-10 + 25 = \(\frac{1}{59049}\) + 25 = \(\frac{1476226}{59049}\)
\(2.5^2-176:2^3\)
\(=\left(2.25\right)-\left(176:8\right)\)
\(=50-22\)
\(=28\)
\(a)\)\(\left(50-6.x\right).18=2^3.3^2.5\)
\(\Leftrightarrow\)\(\left(50-6.x\right).18=8.9.5\)
\(\Leftrightarrow\)\(\left(50-6.x\right).18=360\)
\(\Leftrightarrow\)\(\left(50-6.x\right)=360\div18\)
\(\Leftrightarrow\)\(50-6.x=20\)
\(\Leftrightarrow\)\(6.x=50-20\)
\(\Leftrightarrow\)\(6.x=30\)
\(\Leftrightarrow\)\(x=5\)
\(b)\)\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=7450\)
\(\Leftrightarrow\)\(100x+\left(1+2+3+...+100\right)=7450\)
\(\Leftrightarrow\)\(100x+5050=7450\)
\(\Leftrightarrow\)\(100x=7450-5050\)
\(\Leftrightarrow\)\(100x=2400\)
\(\Leftrightarrow\)\(x=24\)
b.
(x+1)+(x+2)+...+(x+100)=7450
=> 100x + (1+2+3+...+100)=7450
=>100x + (100+1).50=7450
=>100x=2400
=>x=24
\(142-\left[50-\left(2^3.10-2.5\right)\right]\)
= \(142-\left[50-\left(80-10\right)\right]\)
= \(142-\left(50-70\right)\)
= \(142-\left(-20\right)\)
= \(162\)
\(142-\left[50-\left(2^3\cdot10-2\cdot5\right)\right]\)
\(=142-50+80+10\)
\(=72+90\)
=162