Question

[♡Ƥɦαŋ☆ℒê☆ℌʉүềŋ☆Ąŋɦ♡]

Rút gọn P

\(P=\left(\frac{\sqrt{a}+1}{\sqrt{ab}+1}+\frac{\sqrt{ab}+\sqrt{a}}{\sqrt{ab}-1}-1\right):\left(\frac{\sqrt{a}+1}{\sqrt{ab}+1}-\frac{\sqrt{ab}+\sqrt{a}}{\sqrt{ab}-1}+1\right)\)

Cần gấp nhé mọi người >_< tớ cần giải nhanh trong chiều nay!!!!

Answer 1

[Darlingg🥝]

Cảm ơn chú đã kb giờ thì t sẽ làm hộ chú :V

\(P=\left(\frac{\sqrt{a}+1}{\sqrt{ab}+1}+\frac{\sqrt{ab}+\sqrt{a}}{\sqrt{ab}-1}-1\right):\left(\frac{\sqrt{a}+1}{\sqrt{ab}+1}-\frac{\sqrt{ab}+\sqrt{a}}{\sqrt{ab}-1}+1\right)\)

\(P=\left[\frac{\left(\sqrt{a}+1\right)\left(\sqrt{ab}-1\right)}{\left(\sqrt{ab}+1\right)\left(\sqrt{ab}-1\right)}+\frac{\left(\sqrt{ab}+\sqrt{a}\right)\left(\sqrt{ab}+1\right)}{\left(\sqrt{ab}-1\right)\left(\sqrt{ab}+1\right)}-\frac{ab-1}{ab-1}\right]\)

\(:\left[\frac{\left(\sqrt{a}+1\right)\left(\sqrt{ab}-1\right)}{\left(\sqrt{ab}+1\right)\left(\sqrt{ab-1}\right)}\right]-\frac{\left(\sqrt{ab}+\sqrt{a}\right)\left(\sqrt{ab}+1\right)}{\left(\sqrt{ab}-1\right)\left(\sqrt{ab}+1\right)}+\frac{ab-1}{ab-1}\)

\(P=\frac{\left(a\sqrt{b}-\sqrt{a}+\sqrt{ab}-1\right)+\left(ab+\sqrt{ab}+a\sqrt{b}+\sqrt{a}\right)-\left(ab-1\right)}{ab-1}\)

\(:\frac{\left(a\sqrt{b}-\sqrt{a}+\sqrt{ab}-1\right)-\left(ab+\sqrt{ab}+a\sqrt{b}+\sqrt{a}\right)+\left(ab-1\right)}{ab-1}\)

\(P=\frac{a\sqrt{b}-\sqrt{a}+\sqrt{ab}-1+ab+\sqrt{ab}+a\sqrt{b}+\sqrt{a}-ab+1}{ab-1}\)

\(:\frac{a\sqrt{b}-\sqrt{a}+\sqrt{ab}-1-ab-\sqrt{ab}-a\sqrt{b}-\sqrt{a}+ab-1}{ab-1}\)

\(P=\frac{2a\sqrt{b}+2\sqrt{ab}}{ab-1}:\frac{-2\sqrt{a}-2}{ab-1}\)

\(P=\frac{2\sqrt{ab}\left(\sqrt{a}+1\right)}{ab-1}.\frac{ab-1}{-2\left(\sqrt{a}+1\right)}=-\sqrt{ab}\)

P/s: :V bài này tính toán kĩ nhưng chưa chắc đúng :VVVV

Answer 2

[♡Ƥɦαŋ☆ℒê☆ℌʉүềŋ☆Ąŋɦ♡]

Mr.Fuff cảm ơn ạ >_<!!!!