A=(2002-79+15)-(-79+15).Tìm A
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a, ( 2002 - 79 + 15 ) - ( -79 + 15 )
= 2002 -79 +15 +79 -15
= 2002
b, - ( 515 - 80 +91 ) - ( 2003 + 80 - 91 )
= -515 + 80 -91 -2003 - 80 +91
= -2518
(1267 - 196) - (267 - 204)
= 1267 - 196 - 267 + 204
= (1267 - 267) + (204 - 196)
= 1000 + 8
= 1008
(3965 - 2378) - (437 - 1378) - 528
= 3965 - 2378 - 437 + 1378 - 528
= 3965 - (437 + 528) - (2378 - 1378)
= 3965 - 965 - 1000
= 3000 - 1000
= 2000
2002 - 79 + 15 - (-79) - 15
= 2002 - (79 - 79) + (15 - 15)
= 2002 - 0 + 0
= 2002
-329 - (15 - 101) - (25 - 440)
= - 329 - 15 + 101 - 25 + 440
= (440 + 101 - 329) - (15 + 25)
= (541 - 329) - 40
= 212 - 40
= 172
\(a)-7105-\left(155-7105\right)\)
\(=-7105-155+7105\)
\(=-7260+7105\)
\(=-155\)
\(b)35+75+\left(345-35-75\right)\)
\(=35+75+345-35-75\)
\(=110+345-35-75\)
\(=455-35-75\)
\(=420-75\)
\(=345\)
\(c)\left(2002-79+15\right)-\left(-79+15\right)\)
\(=2002-79+15+79+15\)
\(=1923+15+79+15\)
\(=1938+79+15\)
\(=2017+15\)
\(=2032\)
\(d)-\left(515-80+891\right)-\left(2003+80-91\right)\)
\(=-515-80+891-2003-80+91\)
\(=-595+891-2003-80+91\)
\(=296-2003-80+91\)
\(=-1707-80+91\)
\(=-1787+91\)
\(=-1696\)
(35+75)+(345-35-75)
=35+75-345-35-75
=(35-35)+345+975-75)
(2002-79+15)-(-79+15)
=2002-79+15+79-15
=2002+(79-79)+915-15)
=2002.
-(515-80+91)-(2003+80-91)
=-515+80-91-2003-80+91
(-515)-2003+(80-80)+(91-91)
=2518.
( 35 + 75 ) + ( 345 - 35 - 75 )
= 35 + 75 + 345 - 35 - 75
= ( 35 - 35 ) + ( 75 - 75 ) + 345
= 0 + 0 + 345
= 345
( 2002 - 79 + 15 ) - ( -79 + 15 )
= 2002 - 79 + 15 + 79 - 15
= 2002 + ( -79 + 79 ) + ( 15 - 15 )
= 2002 + 0 + 0
= 2002
- ( 515 - 80 + 91 ) - ( 2003 + 80 - 91 )
= -515 + 80 - 91 - 2003 - 80 + 91
= -515 + ( 80 -80 ) + ( -91 + 91 ) - 2003
= -515 + 0 + 0 - 2003
= - 2518
( 35 + 75 ) + ( 345 - 75 - 35 )
= 35 + 75 + 345 - 75 - 35
= ( 35 + 75 ) - ( 75 + 35 ) + 345
= 110 - 110 + 345
= 0 + 345
= 345
A. (35 + 75) + (345 - 35 - 75)
= 35 + 75 + 345 - 35 - 75
= (35 - 35) + (75 - 75) + 345
= 0 + 0 + 345
= 345
B. (2002 - 79 + 15) - (-79 + 15)
= 2002 - 79 + 15 + 79 - 15
= 2002 + (-79 + 79) + (15 - 15)
= 2002 + 0 + 0
= 2002
C. - (515 - 80 + 91) - (2003 + 80 - 91)
= -515 + 80 - 91 - 2003 - 80 + 91
= -515 - 2003 + (80 - 80) + (-91 + 91)
= -2518 + 0 + 0
= -2518
#Học tốt!!!
~NTTH~
<Cho hỏi ai k sai mik vậy, nếu sai làm ơn giải thử, nếu có thể chỉ ra lỗi sai của mik, đừng k sai trong khi câu trả lời là đúng>
1) ( 2002 - 79 + 15 ) - ( -79 + 15 ) = 2002
2) - (515 - 80+ 91 ) - ( 2003 + 80 + 91 ) = -2700
3) 4573 + 46 - 4573 + 35 - 16 - 5 = 60
4) 32 + 34 + 36 + 38 - 10 - 12 - 14 - 16 - 18 = 70
Bài 1:
a) \(24 - (-15) - 2\)
\(=39-2\)
\(=37\)
b) \((-85) + 10 - (-85) - 50\)
\(=[(-85)-(-85)]+10-50\)
\(=0+10-50\)
\(=10-50\)
\(=-40\)
c) \(71 - (-30) - (+18) + (-30)\)
\(=[(-30)-(-30)]+71-(+18)\)
\(=0+71-18\)
\(=71-18\)
\(=53\)
d) \(-(30) - (+37) + (+37) + (-85)\)
\(=[-(+37)+(+37)]-(30)+(-85)\)
\(=0-(30)+(-85)\)
\(=(-30)+(-85)\)
\(=-115\)
e) \((35-815) - (795-65)\)
\(=(-780)-730\)
\(=-1510\)
g) \((2002-79+15) + (-79+15)\)
\(=1938+(-64)\)
\(=1874\)
Bài 2:
a) \(25 - (30+x) = x - (27-8)\)
\(25-30-x=x-27+8\)
\(x+x=25-30+27-8\)
\(2x=14\)
\(x=14\div2\)
\(x=7\)
b) \((x-12) - 15 = (20-17) - (18+x) \)
\(x-12-15=13-18-x\)
\(x-27=-5-x\)
\(x+x=-5+27\)
\(2x=22\)
\(x=22\div2\)
\(x=11\)
c) \(15 - x = 7 - (-2)\)
\(15-x=9\)
\(x=15-9\)
\(x=6\)
d) \(x - 35 = (-12) - 3\)
\(x-35=-15\)
\(x=-15+35\)
\(x=20\)
e) \(\left|5-x\right|-26=-15\)
\(\left|5-x\right|=-15+26\)
\(\left|5-x\right|=11\)
Từ đây ta có:
*Nếu \(5-x=11\)
\(x=5-11\)
\(x=-6\)
*Nếu \(5-x=-11\)
\(x=5-(-11)\)
\(x=16\)
Vậy \(x=-6;x=16\)
Kết quả lun :
\(A=\)\(2002-79+15+79-15\)
\(A=2002+\left(-79\right)+15+79+\left(-15\right)\)
\(A=2002+\left(-79+79\right)+\left(-15+15\right)\)
\(A=2002+0+0\)
\(A=2002\)
Ta có: A= (2002-79+15)- (-79+15)
= 2002-79+15+79-15
= (-79+79)+(15-15)+2002
= 0+0+2002
= 2002
Vậy A= 2002
_Học tốt nha_