Bài 1:Thực hiện phép tính:
1,\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
2,\(-12:(\frac{3}{4}-\frac{5}{6})^2\)
3,\(\frac{7}{23}.[(-\begin{matrix}8\\6\end{matrix})-\frac{45}{18}]\)
4,\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
5,\((1+\frac{2}{3}-\frac{1}{4})(0,8-\frac{3}{4})^2\)
6,\(16\frac{2}{7}:(\frac{-3}{5})+28\frac{2}{7}:\frac{3}{5}\)
7,\((2^2:\frac{4}{3}-\frac{1}{2}).\frac{6}{5}-17\)
8,\((\frac{1}{3})^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)
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Đọc tiếp
Bài 1:Thực hiện phép tính:
1,\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
2,\(-12:(\frac{3}{4}-\frac{5}{6})^2\)
3,\(\frac{7}{23}.[(-\begin{matrix}8\\6\end{matrix})-\frac{45}{18}]\)
4,\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
5,\((1+\frac{2}{3}-\frac{1}{4})(0,8-\frac{3}{4})^2\)
6,\(16\frac{2}{7}:(\frac{-3}{5})+28\frac{2}{7}:\frac{3}{5}\)
7,\((2^2:\frac{4}{3}-\frac{1}{2}).\frac{6}{5}-17\)
8,\((\frac{1}{3})^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)
9,\(\frac{3}{5}:(\frac{-1}{15}-\frac{1}{6})+\frac{3}{5}:(\frac{-1}{3}-1\frac{1}{15})\)
10,\(\left(-6,5\right).5,7+5,7.\left(-3,5\right)\)
11,\(10.\sqrt{0,01.\frac{16}{9}+3\sqrt{49}-\frac{1}{6}\sqrt{ }4}\)
12,\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
b) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)
\(=1+\left(-1\right)+0,5\)
\(=0,5\)
_Học tốt nha_
a, \(\frac{15}{12}\)+ \(\frac{5}{13}\)- \(\frac{3}{12}\)-\(\frac{18}{13}\)
= \(\frac{5}{4}\)+ \(\frac{5}{13}\) - \(\frac{1}{4}\) - \(\frac{18}{13}\)
= \(\left(\frac{5}{4}-\frac{1}{4}\right)\)+ \(\left(\frac{5}{13}-\frac{18}{13}\right)\)
= 1 - 1 = 0
b, \(\frac{11}{24}\)- \(\frac{5}{41}\)+ \(\frac{13}{24}\)+ 0,5 - \(\frac{36}{41}\)
= \(\left(\frac{11}{24}+\frac{13}{24}\right)\)- \(\left(\frac{5}{41}+\frac{36}{41}\right)\)+ 0,5
= 1 - 1 + 0,5 = 0,5
c, \(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)
=\(\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{5}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{5}{11}\)
= \(\frac{11}{5}.\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)
= \(\frac{11}{5}.\left[\left(-\frac{3}{4}-\frac{1}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)\right]\)
= \(\frac{11}{5}.\left[\left(-1\right)+1\right]\)
= 0
d, \(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)
= \(9.\left(0,75-0,25\right)-2\)
= 9. 0,5 - 2 = 2,5
e, \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
= \(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
= -1 + 1 - \(\frac{1}{2}\)
= \(-\frac{1}{2}\)